Answer:
v = 120 m/s
Explanation:
We are given;
earth's radius; r = 6.37 × 10^(6) m
Angular speed; ω = 2π/(24 × 3600) = 7.27 × 10^(-5) rad/s
Now, we want to find the speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator.
The angle will be;
θ = ¾ × 90
θ = 67.5
¾ is multiplied by 90° because the angular distance from the pole is 90 degrees.
The speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator will be:
v = r(cos θ) × ω
v = 6.37 × 10^(6) × cos 67.5 × 7.27 × 10^(-5)
v = 117.22 m/s
Approximation to 2 sig. figures gives;
v = 120 m/s
Answer:
Newton's third law of motion states that for every action, there is equal and opposite reaction.
While space walking, when the astronaut gets detached from the space ship, she floats in space holding a wrench. In order to get back to the spaceship, she should throw the wrench in the opposite direction of the spaceship. This action would cause a reaction on her own body and she would be pushed away from the wrench and towards the spaceship. Thus, she can return back to the spaceship in this way.
Answer:
the rigid outer part of the earth, consisting of the crust and upper mantle.
Explanation:
<h3><u>Answer;</u></h3>
C) Covalent bonds are generally weaker than ionic bonds because they overlap electrons to fill their outer shell.
<h3><u>Explanation;</u></h3>
- <em><u>Covalent bond is a type of bond that results from the sharing of electrons between two non-metal atoms. </u></em>
- <em><u>Ionic bond on the other is a type of bond that results from the transfer of electrons between metal atoms and non metal atoms, where a metal atom looses electrons and a non-metal atom gains electrons.</u></em>
- <em><u>The amount of energy required to break an given bond determines how strong a particular bond is.</u></em> Ionic bonds require more energy to break as compared to covalent bond and therefore they are stronger than the covalent bonds.