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3 years ago

The velocity of a given wave remains the same while the wavelength increases. What happens to the frequency of the wave?

Physics

1 answer:

Degger [83]3 years ago

5 0

Answer:

B. It decreases proportionally to the wavelength

Explanation:

The relationship between wavelength, velocity, and frequency of a wave is given as;

$f = \frac{v}{\lambda}$

where;

f is the frequency of the wave

v is the velocity of the wave

λ is the wavelength

From the equation above, the frequency of a wave is inversely proportional to its wavelength. As the wavelength increases, the frequency decreases and vice versa.

Therefore, the correct option is "B"

B. It decreases proportionally to the wavelength

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Answer:

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Explanation:

This exercise looks at the motion of a positively charged particle in an electric field.

a) Since the field is vertical the acceleration in this direction is

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the electric force is

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b) the positive particle is accelerated towards the negative plate,

The field is descending, for which the event is down

c) where hit the particle on the x-axis

they indicate that the particle leaves the center of the negative plate, for which we will fix our reference system at this point.

Let's find the components of the initial velocity.

sin θ = v_{oy} / v

cos θ = v₀ₓ / v

v_{oy} = v₀ sin θ

v₀ₓ = v₀ cos θ

v_{oy) = 1.02 10⁵ sin 37 = 0.6139 10⁵ m / s

v₀ₓ = 1.02 10⁵ cos 37 = 0.8146 10⁵ m / s

Let's find the time it takes to hit the negative plate

y = y₀I + v_{oy} t + ½ a and t2

in this case the positions are y = y₀ = 0 and the accelerations

a = - 1,616m/s2,

we substitute

0 = 0 + v_{oy} t - ½ a_y t²

v_{oy}= ½ a_y t

t = 2v_{oy} / a_y

let's calculate

t = 2 0.6139 10⁵ / 1.616

t = 7.597 10⁴s

in this time the particle travels a horizontal distance

x = v₀ₓ t

x = 0.8145 10⁵ 7.597 10⁴

x = 6.19 10⁹ m

the particle falls off the plate

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