Most likely the second one (sand letting water run through it) because if you are trying to determine how what moves through soil You would want the one the one that can do that:)
Answer:
The concentration of helium in the water is 2.405×10^-4 M
Explanation:
Concentration = Henry's law constant × partial pressure of helium
Henry's law constant = 3.7×10^-4 M/atm
Partial pressure of helium = 0.65 atm
Concentration = 3.7×10^-4 × 0.65 = 2.405×10^-4 M
Answer:
Explanation:
So here's the thing . Sugar molecule is a molecular solid . It a relatively weak molecule
We all know the formula of glucose ( which is a sugar type molecule ) which is C12 H22 O 11 . This is basically bonded together by dipole dipole forces ( remember that this force of attraction is weak ) .on the other hand you have the solution ( which is usually water) .water is held by strong attraction forces known as hydrogen bonding .since this type of bonding is greater than dipole dipole forces .therefore when glucose is dropped in water . water is easily able to obercome the forces that are keeping the glucose molecule intact . therefore the molecule dissolves and breaks into pieces. Hope this helps
Answer:
Oxygen is limiting reactant
Explanation:
Based on the chemical reaction:
2C2H6 + 7O2 → 6H2O + 4CO2
<em>2 mole of ethane reacts with 7 moles of oxygen</em>
<em />
For a complete reaction of 5.25 moles of ethane are required:
5.25 moles Ethane * (7mol Oxygen / 2mol Ethane) = 18.38 moles of oxygen
As there are just 15.0 moles of oxygen
<h3>Oxygen is limiting reactant</h3>
Answer:
28.9%
Explanation:
Let's consider the following balanced equation.
2 FeS₂ + 11/2 O₂ ⇒ Fe₂O₃ + 4 SO₂
We can establish the following relations:
- The molar mass of Fe₂O₃ is 159.6 g/mol
- 1 mole of Fe₂O₃ is produced per 2 moles of FeS₂
- 1 mole of Fe is in 1 mole of FeS₂
- The molar mass of Fe is 55.84 g/mol
The amount of Fe in the sample that produced 0.516 g of Fe₂O₃ is:
The percent of Fe in 1.25 g of the ore is:
