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3 years ago

PLEASE NO GUESSES OR INCORRECT ANSWERS

1 answer:

3 0

Diffusion is the movement of any chemical from one place to another.
Osmosis is the movement of water across a partially permeable membrane.

I hope this helps!

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What are the laws of Newton?

Tanzania [10]

Answer:

an object that is at rest will stay at rest inless a force acts upon it.

An oject that is in motion will not change its velocity unless a force acts upon it.

4 0

2 years ago

Read 2 more answers

What substance do you place in the burette during a titration

strojnjashka [21]

Answer:

Acid solution

Explanation:

In acid-base titrations carried out in school and college labs, many of the older generation, well-informed teachers told their students that the acid solution should be taken in the burette.

5 0

2 years ago

The elementary reaction 2 H 2 O ( g ) − ⇀ ↽ − 2 H 2 ( g ) + O 2 ( g ) proceeds at a certain temperature until the partial pressu

daser333 [38]

Answer:

6.75 × 10⁻⁸is the value of the equilibrium constant at this temperature.

Explanation:

2H₂O(g) ⇄ 2H₂(g) + O₂(g)

Partial pressure of H₂O = 0.0500 atm

Partial pressure of H₂ = 0.00150 atm

Partial pressure of O₂ = 0.00150 atm

The expression of Kp for the given chemical equation is:

$K_p = \frac{[H_2]^2[O_2]}{H_2O}$

$= \frac{(0.00150^2)(0.00150)}{(0.0500)} \\= 6.75 * 10^-^8$

6.75 × 10⁻⁸is the value of the equilibrium constant at this temperature

7 0

3 years ago

A sample of krypton has a volume of 6.00 L, and the pressure is 0.960 atm. If the final temperature is 55.0°C, the final volume

MissTica

193.38 K was the initial temperature of the krypton.

Explanation:

Data given:

Initial volume of the krypton gas = 6 litres

initial pressure of the krypton gas = 0.960 atm

initial temperature of the krypton gas = ?

final volume of the krypton gas = 7.70 litres

final pressure of the Krypton gas = 1.25 atm

final temperature of the krypton gas = 55 degrees or 273.25+55 = 323.15 K

Applying the Combined Gas Laws:

$\frac{P1V1}{T1} = \frac{P2V2}{T2}$

Rearranging the equation:

T1 = $\frac{P1V1T2}{P2V2}$

Putting the value in the equation:

T1 = $\frac{0.960 X 6 X 323.15}{1.25 X 7.70}$

T1 = 193.38 K

Initial temperature of the krypton gas is 193.78 K

5 0

3 years ago

I guess this is free:)))): ((((

Eddi Din [679]

Answer:

tysm!!!! :D <<<33333

Explanation:

4 0

2 years ago