The final temperature, t₂ = 30.9 °C
<h3>Further explanation</h3>
Given
24.0 kJ of heat = 24,000 J
Mass of calorimeter = 1.3 kg = 1300 g
Cs = 3.41 J/g°C
t₁= 25.5 °C
Required
The final temperature, t₂
Solution
Q = m.Cs.Δt
Q out (combustion of compound) = Q in (calorimeter)
24,000 = 1300 x 3.41 x (t₂-25.5)
t₂ = 30.9 °C
The answer for this question is D.
Answer:
1)
(500.mL)(.200M)/.150M = 667 mL
667mL - 500mL = 167mL of water is needed
2)
1.0 L = 1000mL
M1 V1 = M2 V2
(1.6 mol/L) (175 mL) = (x)(1000mL)
x = .28M
4 Quantum numbers are used
1.Azimuthal
2.Principal
3.Spin
4.Magnetic
Answer: -
The acceleration due to gravity at height r = a = GM/r²
Rearranging
r² = GM /a
= (6.674 x 10⁻¹¹ x 5.972 x 10²⁴ ) / 5
r = 8.917 x 10⁶ m
r = 8917 Km
Now Radius of earth = 6371 Km
So height = 8917 - 6371 = 2546 Km
