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belka [17]
4 years ago
5

I need help please help me

Physics
1 answer:
suter [353]4 years ago
6 0
B)Saturn is the answer you are looking for
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The noble gases have eight valence electrons and as a result are
AURORKA [14]
The noble gases have eight valence electrons and as a result are stable. 

If an atom consists of 8 valence electrons, they have a full octet, and do not need to bond, which makes them "happy".
4 0
4 years ago
How you would orient the magnets and what you would do with the magnets to achieve maximum repulsion
Westkost [7]

The orientation of the magnets that gives the strongest repulsion because these poles and facing each other that is then leaves highest flux density of the poles for a force of repulsion to be very high

3 0
3 years ago
A woman standing before a cliff claps her hands, and 2.8s later she hears the echo. How far away is the cliff? The speed of soun
ella [17]

Answer:

480.2 m

Explanation:

The following data were obtained from the question:

Speed of sound (v) = 343 m/s.

Time (t) = 2.8 s

Distance (x) of the cliff =?

The distance of the cliff from the woman can be obtained as follow:

v = 2x /t

343 = 2x /2.8

Cross multiply

2x = 343 × 2.8

2x = 960.4

Divide both side by the coefficient of x i.e 2

x = 960.4/2

x = 480.2 m

Therefore, the cliff is 480.2 m away from the woman.

4 0
3 years ago
Calculate the wavelength (in nm) of light that produces its first minimum at an angle of 21.0° when falling on a single slit of
Cerrena [4.2K]

To solve this problem it is necessary to apply the related concepts to the principle of overlap, specifically to single slit diffraction experiment concept.

Mathematically this can be expressed as:

dsin\theta = m\lambda

Where,

d = Width of the slit

\lambda =Wavelength

\theta = Angle relative to the original direction of the light

m = Any integer which represent the order of the equation (number of repetition of the spectrum)

To solve the problem we need to rearrange the equation and find the wavelength

\lambda = \frac{dsin\theta}{m}

Our values are given as,

d = 1.46\mu m = 1.46*10^{-6}m

\theta = 21\°

m = 1

Replacing in our equation we have,

\lambda = \frac{dsin\theta}{m}

\lambda = \frac{(1.46*10^{-6})sin(21)}{1}

\lambda = 5.232*10^{-7}m

\lambda = 523.2nm

Therefore the wavelength is 523.2nm

7 0
4 years ago
What is the gravity force between two stars with mass of 5,000,000 kg and 1,000,000 kg if the distance between them is 100 m
Luda [366]

Answer:

0.0334N

Explanation:

Given parameters:

M1  = 5 x 10⁶kg

M2  = 1 x 10⁶kg

Distance  = 100m

Unknown:

Gravitational force  = ?

Solution:

To solve this problem, we use the Newton's law of universal gravitation.

     Fg  = \frac{G m1 m2}{r^{2} }  

G is the universal gravitation constant

m is the mass

r is the distance

         Fg  = \frac{6.67 x 10^{-11} x 5 x 10^{6}  x 1 x 10^{6} }{100^{2} }   = 0.0334N

8 0
3 years ago
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