Looks correct but the second to last I would of put abiotic and biotic factors but I don’t know what’s right for you
Answer:

Explanation:
Hello there!
In this case, since the combustion of B2H6 is:

Thus, since there is 1:2 mole ratio between the reactant and product, the produced grams of the latter is:


Best regards!
In chemical reactions, the actual yield is not the same as the expected yield . Actual yield is lower than the theoretical yield . Then we have to find the yield percentage. To see what percentage of the theoretical yield is the actual yield.
Percent yield = actual yield / theoretical yield x 100%
Percent yield = 24.6/55.9 x100%
Percent yield = 44%
Answer:
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Explanation:
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