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slega [8]
3 years ago
13

In 2009, Melissa developed a hydrogen powered engine for a car while working in her garage in her spare time. Melissa installed

the engine in a small car that she has been driving around town. In 2012, engineers working for Ford Motor Co. independently developed an identical hydrogen powered engine. After completing tests on the engine for two years, Ford filed a patent for the engine on March 1, 2014. On March 2, 2014, Melissa also filed for a patent for her engine. Assuming the engine satisfies all of the requirements for a patent, who is entitled to the patent?
Physics
1 answer:
adoni [48]3 years ago
7 0

Answer:

Ford

Explanation:

It's true that Melissa was the first person to develop a hydrogen powered engine for a car. The efforts of engineers from Ford Motor Co. were also independent and they also developed a similar engine as Melissa. Now when it comes to records of filing patent, Ford Motor was the first and as per the rules of patenting, the first person or organization to file patent is entitled to the patent. Therefore, Ford deserves the patent.

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A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a rope that goes over an ideal pulley. If the masses are
irga5000 [103]

Answer:

The time taken will be 0.553 seconds.

Explanation:

We should start off by finding the force exerted by the rope on the 3kg weight in this case.

Weight of 5kg mass = 5 * 9.81 = 49.05 N

Weight of 3kg mass = 3 * 9.81 = 29.43 N

The force acting upward on the 3kg mass will equal the weight of the 5kg mass. Thus the resultant force acting on the 3kg mass is:

Total force = 49.05 - 29.43 = 19.62 N (upwards)

We can now find the acceleration:

F = m * a

19.62 = 3 * a

a = 6.54 m/s^2

We now use the following equation of motion to get the time taken to travel 1 meter:

s=u*t+\frac{1}{2} (a*t^2)

1=0*t+\frac{1}{2} (6.54*t^2)

t = 0.553 seconds

4 0
3 years ago
An earthquake in San Francisco produces a wave with a period of 0.80 seconds and a wavelength of 40 m., How long will it take fo
gtnhenbr [62]

Answer:

A) 3.11 Hrs

Explanation:

Wave speed is given by the formula

Speed = \frac{wavelength}{Time\: period}

now we will have

speed = \frac{40}{0.80}

v = 50 m/s

now the time taken by the wave to move the distance 560 km is given as

t = \frac{distance}{speed}

t = \frac{560\times 10^3}{50}

t = 11200 s

t = 3.11 hours

4 0
3 years ago
Dust particles in air have a typical mass of 5.0 x 10-16 kg. They undergo irregular motion due to collisions with air molecules.
Mars2501 [29]

Answer:

Rms speed of the particle will be  38.68\times 10^8m/sec

Explanation:

We have given mass of the air particle m=5\times 10^{-16}kg

Gas constant R = 8.314 J/mol-K

Temperature is given T = 27^{\circ}C=273+27=300K

We have to find the root mean square speed of the particle

Which is given by v_{rms}=\sqrt{\frac{3RT}{m}}=\sqrt{\frac{3\times 8.314\times 300}{5\times 10^{-16}}}=38.68\times 10^8m/sec

So rms speed of the particle will be 38.68\times 10^8m/sec

5 0
3 years ago
If you climb to the top of Mt. Everest, you will be 8850 m (about 5.50 mi) above sea level.
Umnica [9.8K]

Answer:

9.773m/s2

Explanation:

Given,

h=8848m

The value of sea level is 9.08m/s2

So,

Let g′ be the acceleration due to the gravity on the Mount Everest.

g′=g(1−h2h)

=9.8(1−640000017696)

=9.8(1−0.00276)

9.8×0.99724

=9.773m/s2

Thus, the acceleration due to gravity on the top of Mount Everest is =9.773m/s2

Hope it helped!!!

5 0
2 years ago
Question 2 (1 point)
sveticcg [70]
according to the facts it should be a numerous amount of wrong answers so ignore dis
7 0
2 years ago
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