It can be described as <span>a pure substance and an element. </span>
Answer:
S = V t where S is the horizontal distance traveled
1/2 g t^2 = H where H is the vertical distance traveled
t^2 = 2 H / g
V^2 = S^2 / t^2 = S^2 g / (2 H) combining equations
tan theta = H / S
V^2 = S g / (2 tan theta)
Using S = L cos theta
V^2 = L g cos theta / (2 tan theta)
Giving V in terms of L and theta
Answer:
Explanation:
s = s₀ + v₀t + ½at²
s = 0 + 0(15) + ½(6)(15²)
s = 675 m
Not sure what the free fall acceleration is needed for, but if the object is dropped from a high enough point, it will travel in 15 seconds
s = ½10(15²) = 2250 m if air resistance is ignored
The situation given above can be answered through the concept of the First Law of thermodynamics which states that the change in internal energy is equal to the difference between the work done and the heat added to the system. The work done by the object is negative and the heat added is positive.
change in internal energy = -500J + 1400 J = 900 J
Answer:
<h3>The answer is 4.53 kgm/s</h3>
Explanation:
The momentum of an object can be found by using the formula
<h3>momentum = mass × velocity</h3>
From the question
mass = 62 g = 0.062 kg
velocity = 73 m/s
We have
momentum = 0.062 × 73 = 4.526
We have the final answer as
<h3>4.53 kgm/s</h3>
Hope this helps you