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nekit [7.7K]
3 years ago
8

Light of a given wavelength is used to illuminate the surfacce of a metal, however, no photoelectrons are emitted. In order to c

ause electrons to be ejected from the surface of this metal you shouldA. use light of the same wavelength but increase its intensity.B. use light of a shorter wavelength.C. use light of the same wavelength but decrease its intensity.D. use light of a longer wavelength.
Physics
1 answer:
Jlenok [28]3 years ago
6 0

Answer:

B. use light of a shorter wavelength.

Explanation:

We know that

E= \frac{hc}{\lambda}

h= plank's constant

c= speed of light

λ= wavelength of the incident light

so, in order to have sufficient energy for for the emission of electron, the incident's radiation must have λ small enough.

B. use light of a shorter wavelength.

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The driver of a car traveling 110 km/h slams on the brakes so that the car undergoes a constant acceleration, skidding to a comp
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Answer: -6.80\ ms^{-2}

Explanation:

We know that the formula for acceleration is given by:

a=\dfrac{v-u}{t} , where v = Final velocity

u= Initial velocity

Given :  The driver of a car traveling 110 km/h slams on the brakes so that the car undergoes a constant acceleration.

i.e. u=   110 km/h =\dfrac{110\times1000}{3600}\approx35.6\ m/s  [∵  1 km= 100 meters and 1 hour = 3600 seconds]

v=  0  m/s ( At brake , final velocity becomes 0)

t=4.5 seconds  

Substitute all the values in the formula , we get

a=\dfrac{0-30.56}{4.5}\approx-6.80\ ms^{-2}

Hence, the average acceleration of the car during braking is -6.80\ ms^{-2}.

5 0
3 years ago
Coulomb's law is expressed mathematically as
nataly862011 [7]
Force between two charges  = 

     ( 1/4πε₀ ) · (Charge #1) · (Charge #2) / (Distance between them)²

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If the force is negative, the charges are attracting.
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3 years ago
When you ride a bike and make a turn, you can feel your body trying to
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Answer:first law

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When driving across Death Valley in the summertime, it is recommended that you release some air from your tires before making th
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Read 2 more answers
Two cars start from rest at a red stop light. When the light turns green, both cars accelerate forward. The blue car accelerates
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First, create an illustration of the motion of the two cars as shown in the attached picture. The essential equations used is

For constant acceleration:
a = v,final - v,initial /t

The solutions is as follows:

 a = v,final - v,initial /t
 3.8 = (v - 0)/2.8 s
 v = 10.64 m/s
 After 2.8 seconds, the speed of the blue car is 10.64 m/s.

4 0
3 years ago
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