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LiRa [457]
3 years ago
11

Select the correct answer. Which healthy snack can provide protein after physical activity? A. an orange slice B. pretzels C. yo

gurt D. a sports drink
Physics
1 answer:
givi [52]3 years ago
4 0

Answer:

From the given choices, the healthy snack that can provide protein after physical activity is the third option, yogurt. Yogurts are derived from fermentation of raw materials by the healthy bacteria, usually of lactobacillus origin. Other items in the choices are not able to provide protein. 

Explanation:

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What happens when an immovable object meets an unstoppable force?”
Alisiya [41]

Answer:

Sorry to tell you this but there’s no answer for that

Explanation:

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3 years ago
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An open 1-m-diameter tank contains water at a depth of 0.7 m when at rest. As the tank is rotated about its vertical axis the ce
Mamont248 [21]

Answer:

Explanation:

To find the angular velocity of the tank at which the bottom of the tank is exposed

From the information given:

At rest, the initial volume of the tank is:

V_i = \pi R^2 h_i --- (1)

where;

height h which is the height for the free surface in a rotating tank is expressed as:

h = \dfrac{\omega^2 r^2}{2g} + C

at the bottom surface of the tank;

r = 0, h = 0

∴

h = \dfrac{\omega^2 r^2}{2g} + C

0 = 0 + C

C = 0

Thus; the free surface height in a rotating tank is:

h=\dfrac{\omega^2 r^2}{2g} --- (2)

Now; the volume of the water when the tank is rotating is:

dV = 2π × r × h × dr

Taking the integral on both sides;

\int \limits ^{V_f}_{0} \ dV = \int \limits ^R_0 \times 2 \pi \times r \times h \ dr

replacing the value of h in equation (2); we have:

V_f} = \int \limits ^R_0 \times 2 \pi \times r \times ( \dfrac{\omega ^2 r^2}{2g} ) \ dr

V_f = \dfrac{ \pi \omega ^2}{g} \int \limits ^R_0 \ r^3 \ dr

V_f = \dfrac{ \pi \omega ^2}{g} \Big [  \dfrac{r^4}{4} \Big]^R_0

V_f = \dfrac{ \pi \omega ^2}{g} \Big [  \dfrac{R^4}{4} \Big] --- (3)

Since the volume of the water when it is at rest and when the angular speed rotates at an angular speed is equal.

Then V_f  =  V_i

Replacing equation (1) and (3)

\dfrac{\pi \omega^2}{g}( \dfrac{R^4}{4}) = \pi R^2 h_i

\omega^2 = \dfrac{4g \times h_i }{R^2}

\omega =\sqrt{ \dfrac{4g \times h_i }{R^2}}

\omega = \sqrt{\dfrac{4 \times 9.81 \ m/s^2 \times 0.7 \ m}{(0.5)^2} }

\omega = \sqrt{109.87 }

\mathbf{\omega = 10.48 \ rad/s}

Finally, the angular velocity of the tank at which the bottom of the tank is exposed  = 10.48 rad/s

6 0
3 years ago
How are electrical current measured
katrin2010 [14]

Answer:

ammeter

Explanation:

hope this helps

6 0
3 years ago
Direction of current in a solenoid depends on the direction of magnetic field
cestrela7 [59]

Explanation:

Its direction depends on the direction of the current. ... When the current flows through the solenoid in the clockwise direction, then the magnetic lines of force inside or center of the coil will be along the axis inwards according to Fleming's right hand rule.

3 0
3 years ago
A plane leaves the airport in Galisteo and flies 170 km at 68.0° east of north; then it changes direction to fly 230 km at 36.0°
luda_lava [24]

Answer:

The direction will be 84.86^\circ and the distance 250.75km.

Explanation:

Let's say A is the displacement vector which represents the first 170km and B the one for the next 230km. Then the components of these vector will be:

A_x=170cos(68^{\circ})\\ A_y=170sin(68^\circ)\\\\B_x=230cos(-36^\circ)\\B_y=230sin(-36^\circ)

The vector which point from the origin to the final position of the plane will be R=A+B. We sum components on <em>x </em>and <em>y </em>independetly (vector property):

R_x=A_x+B_x=170cos(68^{\circ})+230cos(-36^\circ)=63.68km+186.07km=249.75km

R_y=A_y+B_y=170sin(68^\circ)+230sin(-36^\circ)=157.62km-135.19km=22.43km

If \theta is the direction of R then:

tan(\theta )=\frac{R_x}{R_y} ⇒ \theta = arctan(\frac{R_x}{R_y}) ⇒ \theta = 84.86^\circ.

The distance will be given by the magnitud of the vector R:

R=\sqrt{R_x^2 + R_y^2} ⇒ R=\sqrt{R_x^2 + R_y^2} = 250.75.

4 0
4 years ago
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