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svlad2 [7]
3 years ago
11

A ball is tossed vertically upward from a height of 2 m above the ground with an initial velocity of 10 m/s. What will the veloc

ity of the ball be just before it hits the ground?
Physics
1 answer:
Kamila [148]3 years ago
5 0

Answer:7.746m/s

Explanation:V^2=U^2-2gh

g=10m/s(acceleration due to gravity)

V^2=10^2-2*10*2

V^2=60

V=√60=7.746.

THE VELOCITY OF THE BALL JUST BEFORE IT HIT THE GROUND =V(final velocity)

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Answer:

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Explanation:

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Polycondensation reaction takes place between : 1.2 moles of dicarboxylic acid , 0.4 moles of glycerol and 0.6 moles of ethylene glycol

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i) using statistical theory of floxy

(Pa)c = 0.816

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ii) using Carothers theory

( Pc ) = 0.917

attached below is the detailed solution

B) To Obtain the measured value of critical extent of reaction ( 0.866) 1 mol of Glycerol  will react with 1 mol of dicarboxylic acid, but the same can not be applied to our obtained value because our stoichiometry is different

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What is the function of the labeled structures?<br><br> A: <br><br> B: <br><br> C:
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From this values ​​we can see that the person feels a variation of the acceleration of gravity, feels that he has less weight when he goes in the same direction of the season and that his weight increases when he goes in the opposite direction to the season.

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