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3 years ago

Which is not an example of a force?

Physics

1 answer:

NNADVOKAT [17]3 years ago

7 0

Answer:

possibly A?

Explanation:

just feels right man

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I need help with an assignment a need help can someone help me SCIENCE.

Murljashka [212]

Answer:

ok whats the question?

Explanation:

5 0

3 years ago

Car A (mass 1100 kg) is stopped at a traffic light when it is rearended by car B(mass 1400 kg). Both cars then slide with locke

viva [34]

Answer:

Part a)

$v_a = 3.94 m/s$

Part b)

$v_b = 3.35 m/s$

Part C)

$v_b = 6.44 m/s$

Part d)

Due to large magnitude of friction between road and the car the momentum conservation may not be valid here as momentum conservation is valid only when external force on the system is zero.

Explanation:

Part a)

As we know that car A moves by distance 6.1 m after collision under the frictional force

so the deceleration due to friction is given as

$a = -\frac{F_f}{m}$

$a = -\frac{\mu mg}{m}$

$a = - \mu g$

now we will have

$v_f^2 - v_i^2 = 2ad$

$0 - v_i^2 = 2(-\mu g)(6.1)$

$v_a = \sqrt{(2(0.13)(9.81)(6.1)}$

$v_a = 3.94 m/s$

Part b)

Similarly for car B the distance of stop is given as 4.4 m

so we will have

$v_b = \sqrt{2(0.13)(9.81)(4.4)}$

$v_b = 3.35 m/s$

Part C)

By momentum conservation we will have

$m_1v_{1i} = m_1v_{1f} + m_2v_{2f}$

$1400 v_b = 1100(3.94) + 1400(3.35)$

$v_b = 6.44 m/s$

Part d)

Due to large magnitude of friction between road and the car the momentum conservation may not be valid here as momentum conservation is valid only when external force on the system is zero.

3 0

3 years ago

An oil film with refractive index 1.48 and thickness 290 nm is floating on water and illuminated with white light at normal inci

VikaD [51]

Answer:

572.3 nm

Explanation:

$n_{oil}$ = refractive index of the oil film = 1.48

$t_{oil}$ = thickness of the oil film = 290 nm

$\lambda$ = wavelength of the dominant color

m = order

Using the equation

$2 n_{oil} t_{oil} = (m + 0.5) \lambda$

For m = 0

$2 (1.48) (290) = (0 + 0.5) \lambda$

$\lambda$ = 1716.8 nm

For m = 1

$2 (1.48) (290) = (1 + 0.5) \lambda$

$\lambda$ = 572.3 nm

For m = 2

$2 (1.48) (290) = (2 + 0.5) \lambda$

$\lambda$ = 343.4 nm

Hence the dominant color wavelength is 572.3 nm

8 0

3 years ago

Meme on newtons law of motion (should me made ur self not from any searh engine)

k0ka [10]

He will be a pilot and he will fly the plane over bridges fewwww

8 0

1 year ago

A flare is launched from a life raft with an initial velocity of 192 ft/sec. How many seconds will it take for the flare to retu

DIA [1.3K]

We use the formula,

$h= ut- 16 t^2$

Here, h is the variable represents the height of the flare in feet when it returns to the sea so, h = 0 and u is the initial velocity of the flare, in feet per second and its value of 192 ft/sec.

Substituting these values in above equation, we get

$0 = 192 t - 16 t^2 \\\\ 16 t( 12 - t ) =0 \\\\ t = 12 s$ .

Here, t= 0 neglect because it is the time when the flare is launched.

Thus, flare return to the sea in 12 s.

8 0

3 years ago