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2 years ago

Density is calculated by dividing

1 answer:

4 0

Density is defines as the ratio of mass to volume.

So you measure the mass and volume of a sample, and
divide the mass by the volume, to find the density.

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If the mess of an object______, the weight of an object will _______

Gnom [1K]

Answer:

the same

Explanation:

7 0

2 years ago

After driving a portion of the route, the taptap is fully loaded with a total of 27 people including the driver, with an average

belka [17]

We will define the Total mass to calculate the force, so our values are: $M_p = 69*27=1823Kg\\M_g=15*3=45Kg\\M_c=3*5=15Kg\\M_B=25Kg$

Total Mass $= 1863+45+15+25=1948Kg$

The Weight is,

$F=mg=1948*98=19090.4N$

Through the hook's Law we calculate X.

$F_s=Kx$ , where x is the lenght of compression and K the Spring constant.

We don't have a K-Spring, but we can assume a random value (or simply let the equation in function of K)

$X = \frac{F_s}{x} \\X = \frac{1909.4}{k}$

I assume a value of $K=4*10^4N/m$

$X= \frac{1909.4}{4*10^4} = 0.48m$

6 0

3 years ago

Why is it that, in a spoon, you can see yourself upside down? Bamboozled me for years.

Delvig [45]

Here is your answer.

6 0

2 years ago

Tsunamis are fast-moving waves often generated by underwater earthquakes. In the deep ocean their amplitude is barely noticable,

Andrei [34K]

Answer:

a) V = 195.70 m/s

b) f=3.02 × 10⁻⁴ Hz

c) T = 3311.25 seconds

Explanation:

Given:

Wavelength, λ = 646 Km = 646000 m

Distance traveled = 3410 Km = 3410000 m

Time = 4.84 h = 4.84 × 3600 s = 17424 seconds

a) The speed (V) of the wave is given as

V = distance / time

V = 3410000 m/ 17424 seconds

V = 195.70 m/s

b) The frequency (f) of the wave is given as:

f = V / λ

f= 195.70 / 646000

f=3.02 × 10⁻⁴ Hz

c) The time period (T) is given as:

T = 1/ f

T = 1/ (3.02 × 10⁻⁴) Hz

T = 3311.25 seconds

5 0

2 years ago

A high jumper jumps over a bar that is 2 m above the mat. With what velocity does the jumper strike the mat in the landing area?

docker41 [41]

Answer:

The velocity with which the jumper strike the mat in the landing area is 6.26 m/s.

Explanation:

It is given that,

A high jumper jumps over a bar that is 2 m above the mat, h = 2 m

We need to find the velocity with which the jumper strike the mat in the landing area. It is a case of conservation of energy. let v is the velocity. it is given by :

$v=\sqrt{2gh}$

g is acceleration due to gravity

$v=\sqrt{2\times 9.81\ m/s^2\times 2\ m}$

v = 6.26 m/s

So, the velocity with which the jumper strike the mat in the landing area is 6.26 m/s. Hence, this is the required solution.

8 0

3 years ago