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Nana76 [90]
3 years ago
11

A sealed container filled with argon gas at 35°C has a pressure of 832 torr. If the volume of the container is decreased by a fa

ctor of two, what will happen to the pressure? You may assume the temperature remains at 35°C.
Chemistry
1 answer:
Tcecarenko [31]3 years ago
8 0
So I can get points duhhhhh
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When the pressure that a gas exerts on a sealed container changes from 1100 bar to 75.5 bar, the temperature changes from k to 2
Serjik [45]
Gay-Lussac's law gives the relationship between pressure and temperature of gas. For a fixed amount of gas, pressure is directly proportional to temperature at constant volume.
P/T = k
where P - pressure , T - temperature and k - constant
\frac{P1}{T1} =  \frac{P2}{T2}
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
substituting the values in the equation 
\frac{1100 bar}{T}  =  \frac{75.5 bar}{298 K}
T = 4342 K
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7 0
3 years ago
An increase in temperature results in A) a decrease in the required activation energy while the reaction rate remains constant.
N76 [4]

Answer:

C) an increase in rate of reaction because reactant molecules collide with greater energy

Explanation:

Temperature is one of the factors that affect the rate of a reaction. The rate of a reaction increases with an increase in temperature and vice versa. When the temperature of a reaction increases, the kinetic energy of the reactant molecules increases causing them to react at a faster rate.

The reactant molecules respond to an increase in temperature by colliding at a faster rate due to an increased kinetic energy between the reactant molecules.

7 0
3 years ago
Please help!! I was sick when he went over this
Alexus [3.1K]

Answer:

5.70×10^-11 m

Explanation:

7 0
2 years ago
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