A ball is thrown vertically upwards with a velocity of 9.8 m/s. Its velocity after 1 second will be
1 answer:
GiveN:
- Initial velocity = 9.8 m/s²
- Accleration due to gravity = -9.8 m/s²
- Time taken = 1 s
To FinD:
- Final velocity of the ball?
Step-by-step Explanation:
Using the first Equation of motion,
⇒ v = u + gt
⇒ v = 9.8 + -9.8(1)
⇒ v = 0 m/s
The final velocity is hence <u>0</u><u> </u><u>m</u><u>/</u><u>s</u><u>.</u>
<h3>Note:</h3>- While solving questions of under gravity motions using equations of motion, remember the sign convection to avoid mistakes.
- You can consider positive above the ground and negative for towards it.
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Answer:
a) α = 1.875
b) t = 8 s
Explanation:
Given:
ω1 = 0
ω2 = 15
theta (angular displacement) = 60 rad
*side note: you can replace regular, linear variables in kinematic equations with angular variables (must entirely replace equations with angular variables)*
a) α = ?
(ω2)^2 = (ω1)^2 + 2α(theta)
=
+ 2(α)(60)
225 = 120α
α = 1.875
b)
α = (ω2-ω1)/t
t = (ω2-ω1)/α = (15-0)/1.875 = 8
t = 8 s