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Elena L [17]
3 years ago
12

(a) calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 12.0 g. silver has 47 elect

rons per atom, and its molar mass is 107.87 g/mol.
Chemistry
1 answer:
Jet001 [13]3 years ago
3 0

First calculate for number of moles:

moles Ag = 12 g / (107.87 g / mol)

moles Ag = 0.111 mol

 

Convert to atoms using Avogadros number:

atoms Ag = 0.111 mol * (6.022 x 10^23 atoms / mol)

atoms Ag = 6.7 x 10^22 atoms

 

There are 47 electrons per atom, therefore:

Number of electrons = (6.7 x 10^22 atoms) * (47 electrons / atom)

<span>Number of electrons = 3.15 x 10^24 electrons</span>

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Enter your answer in the provided box.
Lina20 [59]

Answer:

5.06atm

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (Litres)

V2 = final volume (Litres)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

P1 = 1.34 atm

P2 = ?

V1 = 5.48 L

V2 = 1.32 L

T1 = 61 °C = 61 + 273 = 334K

T2 = 31 °C = 31 + 273 = 304K

Using P1V1/T1 = P2V2/T2

1.34 × 5.48/334 = P2 × 1.32/304

7.34/334 = 1.32P2/304

Cross multiply

334 × 1.32P2 = 304 × 7.34

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P2 = 2231.36/440.88

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The final pressure is 5.06atm

6 0
3 years ago
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