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Elena L [17]
2 years ago
12

(a) calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 12.0 g. silver has 47 elect

rons per atom, and its molar mass is 107.87 g/mol.
Chemistry
1 answer:
Jet001 [13]2 years ago
3 0

First calculate for number of moles:

moles Ag = 12 g / (107.87 g / mol)

moles Ag = 0.111 mol

 

Convert to atoms using Avogadros number:

atoms Ag = 0.111 mol * (6.022 x 10^23 atoms / mol)

atoms Ag = 6.7 x 10^22 atoms

 

There are 47 electrons per atom, therefore:

Number of electrons = (6.7 x 10^22 atoms) * (47 electrons / atom)

<span>Number of electrons = 3.15 x 10^24 electrons</span>

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this is not balanced though. we have 3 oxygen on right and 4 on left
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now it is same on both sides. we have to figure out which is limiting reagent with the given amounts of reagents. we do this by comparing the ratio between them in terms of moles. we see that so2 has a coefficient of 2 and o2 has none which implies 1 and so3 has 2. this means that for every 2 moles of so2 reacting with 1 mole of o2, we get 2 moles of so3.

lets convert the given values to moles. to do this we know that molecular weight is measured in grams per mole. we are given grams and need to cancel out the grams to get moles. so the molecular weight:
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so what we startrd with (100g) minus what we needed (22.5g) is what we have left
100 - 22.5 = 77.5g o2
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