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scoundrel [369]
3 years ago
8

Which atom is likely to be more chemically reactive, an atom with a partly filled energy level or an atom with all energy levels

completely filled? explain?
Chemistry
2 answers:
kirill115 [55]3 years ago
7 0

Answer:

The correct option is an atom with a partly filled energy level

Explanation:

An atom with a partially filled energy level means the atom has a partially filled outermost shell which in turn means the atom as valence electrons. The presence of valence electrons in atoms makes them undergo chemical bonding with other atoms of the same/different elements (during chemical reactions).

Atoms with completely filled energy levels (such as the noble gases) have a completely filled outermost shell and hence do not have valence electrons which can take part in bond formation during chemical reactions and hence these group of atoms have low chemical reactivity.

irina [24]3 years ago
3 0

It is more reactive the atom with a partly filled energy level because is less stable than the other case. Stability is inversely proportional to reactivity.

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A gaseous fuel mixture stored at 747 mmHg and 298 K contains only methane (CH4) and propane (C3H8). When 11.1 L of this fuel mix
Alisiya [41]

Answer:

M_f=38.8\%

Explanation:

From the question we are told that:

Pressure P=747mmHg

Temperature T=298K

Volume V=11.1

Heat Produced Q=780kJ

Generally the equation for ideal gas is mathematically given by

 PV=nRT

 n= (747/760) *11.1/ (0.0821*298)

 n=0.446mol

Therefore

 x+y=0.446

 x=0.446-y .....1

Since

Heat of combustion of Methane=889 kJ/mol

Heat of combustion of Propane=2220 kJ/mol

Therefore

 x(889) + y(2220) = 760 ...... 2

Comparing Equation 1 and 2 and solving simultaneously

 x=0.446-y .....1

 x(889) + y(2220) = 760 ...... 2

 x=0.173

 y=0.273

Therefore

Mole fraction 0f Methane is mathematically given as

 M_f=\frac{x}{n}*100\%

 M_f=\frac{1.173}{0.446}*100\%

 M_f=38.8\%

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3 years ago
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The concentration of reactant and product must also be equal or the same as the time then only it can be an equilibrium reaction.

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