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scoundrel [369]
3 years ago
8

Which atom is likely to be more chemically reactive, an atom with a partly filled energy level or an atom with all energy levels

completely filled? explain?
Chemistry
2 answers:
kirill115 [55]3 years ago
7 0

Answer:

The correct option is an atom with a partly filled energy level

Explanation:

An atom with a partially filled energy level means the atom has a partially filled outermost shell which in turn means the atom as valence electrons. The presence of valence electrons in atoms makes them undergo chemical bonding with other atoms of the same/different elements (during chemical reactions).

Atoms with completely filled energy levels (such as the noble gases) have a completely filled outermost shell and hence do not have valence electrons which can take part in bond formation during chemical reactions and hence these group of atoms have low chemical reactivity.

irina [24]3 years ago
3 0

It is more reactive the atom with a partly filled energy level because is less stable than the other case. Stability is inversely proportional to reactivity.

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Answer:

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Explanation:

A redox reaction will be spontaneous if standard reduction potential (E^{0}) of the reaction is positive. Because it leads to negative standard gibbs free energy change (\Delta G^{0}), which is a thermodynamic condition for spontaneity of a reaction.

E^{0}=E^{0}(reduction)-E^{0}(oxidation)

Where E^{0}(reduction) and E^{0}(oxidation) represents standard reduction potential of reduction half cell and standard reduction potential of oxidation half cell.

(1) Oxidation:         Mg-2e^{-}\rightarrow Mg^{2+} ;  E_{Mg^{2+}\mid Mg}^{0}=-2.38V

Reduction:         Fe^{3+}+3e^{-}\rightarrow Fe ; E_{Fe^{3+}\mid Fe}^{0}=-0.04V

So, E^{0}=E_{Fe^{3+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}=(-0.04+2.38)V=2.34V

Hence this pair will give spontaneous reaction.

(2) Similarly as above, E^{0}=E_{Pb^{2+}\mid Pb}^{0}-E_{Au^{+}\mid Au}^{0}=(-0.13-1.69)V=-1.82 V

Hence this pair will give non-spontaneous reaction.

(3) Similarly as above, E^{0}=E_{Ag^{+}\mid Ag}^{0}-E_{Br_{2}\mid Br^{-}}^{0}=(0.80-1.07)V=-0.27 V

Hence this pair will give non-spontaneous reaction.

(4)  Similarly as above, E^{0}=E_{Li^{+}\mid Li}^{0}-E_{Cr^{3+}\mid Cr}^{0}=(-3.04+0.74)V=-2.30 V

Hence this pair will give non-spontaneous reaction.

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