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Stels [109]
3 years ago
6

A sample of hydrogen is collected in a flask

Chemistry
1 answer:
lesya [120]3 years ago
3 0

the answer is 736 torr

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use the periodic table to select the element from the drop-down menu that has the correct relative electronegativity.
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You need to list the elements but remember that fluorine has the highest electronegativity out of the entire periodic table
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2 years ago
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Which statement is correct regarding the reaction ?
larisa86 [58]

The true statement is that after reaching equilibrium, the rate of forming products and reactants is the same.

<h3>What is true about the given reaction?</h3>

The given reaction shows a reaction between A and B to form CD

The reaction is a reversible reaction.

A reversible reaction is a reaction which can proceed in either of two ways where the reactants can react to form the product and also the products an break down to form the reactants.

In the reaction given, as the concentration of A and b decreases, the concentration of CD increases and vice versa.

At equilibrium, the rate of formation of CD is equal to the the rate of decomposition of CD.

Therefore, the true statement is that after reaching equilibrium, the rate of forming products and reactants is the same.

In conclusion, a reaction at equilibrium has the forward and backward reactions occurring at the sane rate.

Learn more about equilibrium reaction at: brainly.com/question/18849238

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5 0
1 year ago
Anyoneeee know thissss!?
Alekssandra [29.7K]

Answer:

C. 3 and 4

Explanation:

Count H's in formula (each has 4)

- Hope that helped! Please let me know if you need a further explanation.

3 0
3 years ago
Students performed a procedure similar to Part II of this experiment (Analyzing Juices for Vitamin C Content) as described in th
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Students performed a procedure similar to Part II of this experiment (Analyzing Juices for Vitamin C Content) as described in the procedure section. Given that molarity of DCP is 9.98x10-4 M, it took 16.34 ml of DCP to titrate 10 mL of sample.

Amount of ascorbic acid = 0.050 L sample (0.01634 L DCP/0.01 L sample)( 9.98x10-4 mol DCP/L DCP)(1 mol Ascorbic acid/ 1mol DCP)(176.124 g/mol)(1000mg/1g)= 14.36 mg ascorbic acid

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2 years ago
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v = 0.13\frac{L}{smol}}*0.02\frac{mol}{L}*0.02\frac{mol}{L}=5.2*10^{-5}\frac{mol}{sL}
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2 years ago
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