<u>Answer:</u> The element E is Krypton (Kr).
<u>Explanation:</u>
In a nuclear reaction, the total mass and total atomic number remains the same.
The given nuclear reaction follows:

Total mass on reactant side = total mass on product side
75 = A + 0
A = 75
Total atomic number on reactant side = total atomic number on product side
35 = Z + (-1)
Z = 36
The isotopic symbol of element E is 
Hence, the element E is Krypton (Kr).
Answer:
6 stages
Explanation:
Given:
Copper ore contains:
4.3 wt% water
10.3 wt% CuSO₄
85.3 wt% rock
Feed rate = 11.7 tons per hour
solution produced is to be 10 wt% copper sulfate
90 wt% water
Now,
The CuSO₄ supplied through the feed = 10.3 wt% CuSO₄ × Feed rate
= 0.103 × 11.7
= 1.2051 tons per hour
also,
At each stage 2 tons of solution is collected
therefore,
The CuSO₄ collected in each stage
= weight of solution × 10 wt% copper sulfate
= 2 tons per hour × 0.1
= 0.2 tons per hour
also,
98% of the CuSO₄ is to be recovered
thus,
the amount of CuSO₄ to be recovered
= 0.98 × CuSO₄ supplied through the feed
= 0.98 × 1.2051 tons per hour
= 1.180998
Therefore,
The number of stages required = 
=
= 5.90499 ≈ 6 stages
1 mole ------------- 6.02 x 10²³ atoms
0.70 moles -------- ( atoms zinc )
atoms platinum = 0.70 x ( 6.02 x 10²³ ) / 1
<span> = </span>4.2 x 10²³ atoms zinc
<span>hope this helps!</span>
Answer:
pH = 12.8
Explanation:
HF + NaOH → F⁻ + Na⁺ + H₂O
<em>1 mole of HF reacts with 1 mole of NaOH</em>
<em />
Initial moles of HF and NaOH are:
HF = 0.018L × (0.308mol / L) = 5.544x10⁻³mol HF
NaOH = 0.023L × (0.361mol / L) = 8.303x10⁻³mol NaOH
That means moles of NaOH remains after reaction are:
8.303x10⁻³mol - 5.544x10⁻³mol = <em>2.759x10⁻³moles NaOH</em>
Total volume is 18.0mL + 23.0mL = 41.0mL = 0.0410L
Molar concentration of NaOH is
2.759x10⁻³moles NaOH / 0.0410L = 0.0673M = [OH⁻]
pOH = - log [OH⁻] = 1.17
As pH = 14 - pOH
<em>pH = 12.8</em>
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