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Nastasia [14]
3 years ago
5

A baseball is located at the surface of the earth. Which statements about it are correct? (There may be more than one correct ch

oice.) The gravitational force on the ball due to the earth is exactly the same as the gravitational force on the earth due to the ball. The gravitational force on the ball is independent of the mass of the earth. The ball exerts a greater gravitational force on the earth than the earth exerts on the ball. The earth exerts a much greater gravitational force on the ball than the ball exerts on the earth. The gravitational force on the ball is independent of the mass of the ball.
Physics
1 answer:
lakkis [162]3 years ago
3 0

i think that the answer is a)

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Which is not a property of a pure substance
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How is it possible for the same object to have different amounts of gravitational potential energy?
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In Newtonian mechanics, the gravitational energy possessed by a mass, because of the gravitational field produced by a second mass.

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Charge A and charge B are 2.2 m apart. Charge A is 1.0 C, and charge B is
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Charge A and charge B are 2.2 m apart. Charge A is 1.0 C, and charge B is

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What is the reflectivity of a glass surface (n =1.5) in air (n = 1) at an 45° for (a) S-polarized light and (b) P-polarized ligh
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Answer:

a) R_s = 0.092

b) R_p = 0.085

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n = 1 for air

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using Fresnel equation of reflectivity of S and P polarized light

R_s=\left | \dfrac{n_1cos\theta_i-n_2cos\theta_t}{n_1cos\theta_i+n_2cos\theta_t} \right |^2\\R_p=\left | \dfrac{n_1cos\theta_t-n_2cos\theta_i}{n_1cos\theta_t+n_2cos\theta_i} \right |^2

using snell's law to calculate θ t

sin \theta_t = \dfrac{n_1sin\theta_i}{n_2}=\dfrac{sin45^0}{1.5}=\dfrac{\sqrt{2}}{3}

cos \theta_t =\sqrt{1-sin^2\theta_t} = \dfrac{sqrt{7}}{3}

a) R_s=\left | \dfrac{\dfrac{1}{\sqrt{2}}-\dfrac{1.5\sqrt{7}}{3}}{\dfrac{1}{\sqrt{2}}+\dfrac{1.5\sqrt{7}}{3}} \right |^2

R_s = 0.092

b) R_p=\left | \dfrac{\dfrac{\sqrt{7}}{3}-\dfrac{1.5}{\sqrt{2}}}{\dfrac{\sqrt{7}}{3}+\dfrac{1.5}{\sqrt{2}}} \right |^2

R_p = 0.085

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3 years ago
7. A neutral aluminum rod is at rest on a foam insulating base. A negatively charged balloon is brought near one end of the rod
WITCHER [35]

Answer:

If a negatively charged balloon is brought near one end of the rod but not in direct contact, then <u>the negative charges on the balloon repel the same amount of negative charges on the end of the rod that is close to the balloon</u>, and the positive charges stay at the balloon-side of the rod. The total charge of the rod is still zero, but the distribution of the charges are now non-uniform.

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3 years ago
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