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Nastasia [14]
3 years ago
5

A baseball is located at the surface of the earth. Which statements about it are correct? (There may be more than one correct ch

oice.) The gravitational force on the ball due to the earth is exactly the same as the gravitational force on the earth due to the ball. The gravitational force on the ball is independent of the mass of the earth. The ball exerts a greater gravitational force on the earth than the earth exerts on the ball. The earth exerts a much greater gravitational force on the ball than the ball exerts on the earth. The gravitational force on the ball is independent of the mass of the ball.
Physics
1 answer:
lakkis [162]3 years ago
3 0

i think that the answer is a)

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If f3=0 and f1=12n, what does the magnitude of f? 2 have to be for there to be rotational equilibrium? answer numerically in new
lisov135 [29]
Not to good with math im a language and history kinda guy sorry
4 0
3 years ago
PLEASEEEE HEEEEELP!!!!!
8090 [49]

Answer:

Before:

p_{truck}=16400\ kg.m/s

p_{car}=10000\ kg.m/s

After:

p_{truck}=8000\ kg.m/s

p_{car}=8400\ kg.m/s

v_{fcar}=8.4\ m/s

F=9333.33 \ Nw

Explanation:

<u>Conservation of Momentum</u>

Two objects of masses m1 and m2 moving at speeds v1o and v2o respectively have a total momentum of

p_1=m_1v_{1o}+m_2v_{2o}

After the collision, they have speeds of v1f and v2f and the total momentum is

p_2=m_1v_{1f}+m_2v_{2f}

Impulse J is defined as

J=F.t

Where F is the average impact force and t is the time it lasted

Also, the impulse is equal to the change of momentum

J=\Delta p

As the total momentum is conserved:

p_1=p_2

m_1v_{1o}+m_2v_{2o}=m_1v_{1f}+m_2v_{2f}

We can compute the speed of the second object by solving the above equation for v2f

\displaystyle v_{2f}=\frac{ m_1v_{1o}+m_2v_{2o} -m_1v_{1f} }{  m_2 }

The given data is

m_1=2000\ kg

m_2=1000\ kg\\v_{1o}=8.2\ m/s\\v_{2o}=0\ m/s\\v_{1f}=4\ m/s

a) The impulse will be computed at the very end of the answer

b) Before the collision

p_{truck}=2000\cdot 8.2=16400\ kg.m/s

p_{car}=1000\cdot 0=0\ kg.m/s

c) After collision

p_{truck}=2000\cdot 4=8000\ kg.m/s

Compute the car's speed:

\displaystyle v_{2f}=\frac{ 16400+0 -8000 }{ 1000 }

v_{2f}=8.4\ m/s

And the car's momentum is

p_{car}=1000\cdot 8.4=8400\ kg.m/s

The Impulse J of the system is zero because the total momentum is conserved, i.e. \Delta p=0.

We can compute the impulse for each object

J_1=\Delta p_1=2000(4-8.2)=-8400 \N.s

The force can be computed as

\displaystyle F=\frac{J}{t}=-\frac{8400}{0.9}=-9333.33 \ Nw

The force on the car has the same magnitude and opposite sign

7 0
3 years ago
According to Einstein's special theory of relativity, in which frames of reference will all laws of physics apply?
kenny6666 [7]

Answer: Within any frame of reference that is accelerating

Special relativity was proposed on 1905 by Einstein, who developed his theory based on the following two postulates:

1. <em>The laws of physics are the same in all inertial systems. There is no preferential system. </em>

2. <em>The speed of light in vacuum has the same value for all inertial systems. </em>

Focusing on the first postulate, it can be affirmed that <u>any measurement on a body is made with reference to the system in which it is being measured</u>.

Now, taking into account that an inertial reference system is the one that complies with the principle of inertia:

<em>"For a body to have acceleration, an external force must act on it."</em>

The correct answer is  

Within any frame of reference that is accelerating

3 0
3 years ago
Read 2 more answers
What is the maximum distance that a 60.-watt motor may vertically lift a 90.-newton?weight in 7.5 seconds?a. 2.3mb. 5.0mc. 140md
Naddik [55]

Answer:

b. 5.0 m

Explanation:

Power: Power can be defined as the rate at which work is done.

The S.I unit of power is watt (W).

P = W/t ............................................... Equation 1

Where p = power, W = work, t = time.

But

W = F×d..................................... Equation 2

Where F = force, d = maximum distance.

Substituting equation 2 into equation 1

P = F×d/t

making d the subject of the equation above,

d = Pt/F......................................................... Equation 3

<em>Given: F = 90 Newton, P = 60 watt, t = 7.5 seconds.</em>

<em>Substituting these values into equation 3,</em>

<em>d = 60×7.5/90</em>

<em>d = 5 m</em>

Thus the maximum distance is = 5 m

The right option is b. 5.0 m

5 0
3 years ago
A person sits at rest on a chair. The gravitational force on the person (their weight) is one half of an action-reaction pair. W
Feliz [49]

Normal is the  other half of an action-reaction pair

If a person is sitting on a chair , there must be a gravitation force acting in downward direction which is equal to the weight of that person . That means the person is exerting a force on the chair equal to its weight . But the person is not falling down the chair , because of newtons third law of motion .

There must be a counter force which is equal and opposite to the force exerted by the person on the chair , in order to make net force equal to zero and to make that man in stationary state ( no movement )  .That force is called Normal force which is been acted by the chair on the person .This implies Normal is the  other half of an action-reaction pair

learn more about Force:

brainly.com/question/14110395?referrer=searchResults

#SPJ4

7 0
1 year ago
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