Answer:
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F=m*a=>a=F/m=10000/1267=7.89 m/s²
d=v₀t+a't²/2<=>394.6=112.5*a'=>a'=3.5
a-a'=7.89-3.5=4.39 m/s²
This difference causes friction forces
We apply the second principle of dynamics: vector: F + N + G + Ff = ma (vector vectors, I can not here)
Scalar: Ox: F-Ff = ma
Oy N-mg = 0
Ff = -ma+ F =-1267*7.89+10000=-8869+10000=1131 N
This frictional force (Ff) is opposite to the traction (F)
Answer:
Net force, F = 44.66 N
Explanation:
It is given by,
Initial velocity of the person, u = 0
Final velocity of the person, v = 0.68 m/s
Distance, s = 0.428 m
Combined mass of the person and the kayak, m = 82.7 kg
We need to find the net force acting on the kayak i.e.
F = ma...........(1)
Firstly, we will calculate the value of "a" from third equation of motion as :
Put the value of a in equation (1) as :
F = 44.66 N
So, the net force acting on the kayak is 44.66 N. Hence, this is the required solution.
In stars more massive than the sun, the core temperature is hotter, which allows for fusion of more complex elements.
Most of the fusion occurs in the core.
In stars more massive than the sun, fusion continues through Deuterium, Carbon, and finally reaching iron/nickel.
Up to this point, the fusion reaction was endothermic, which means that the energy expended to produce the fusion reaction was exceeded by the energy produced in the reaction.
Fusion past iron is exothermic, and therefore the star will be able to survive by fusing elements heavier than iron.
After the core is almost entirely iron, the star is no longer in the Main Sequence.
So, fusion in stars more massive than the sun continue fusing until the core is almost entirely <em>iron</em>.
