Answer:
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Answer:
A IS THE ANSWER
Explanation:
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Answer: find the attached figure for a and b
Explanation:
A) The second figure depict electric field lines and equipotential lines for two equal but opposite charges. The equipotential lines can be drawn by making them perpendicular to the electric field lines. The potential is greatest (most positive) near the positive charge and least (most negative) near the negative charge.
B) The figure attached depicts an isolated point charge Q with its electric field lines in blue and equipotential lines in green. The potential is the same along each equipotential line, meaning that no work is required to move a charge anywhere along one of those lines. Work is needed to move a charge from one equipotential line to another. Equipotential lines are perpendicular to electric field lines in every case.
Please find the attached file for the figure
Answer : Tension in the line = 936.7 N
Explanation :
It is given that,
Mass of student, m = 65 kg
The angle between slackline and horizontal, 
The two forces that acts are :
(i) Tension
(ii) Weight
So, from the figure it is clear that :




Hence, this is the required solution.
The units for G must be ![[N][m^2][kg^{-2}]](https://tex.z-dn.net/?f=%5BN%5D%5Bm%5E2%5D%5Bkg%5E%7B-2%7D%5D)
Explanation:
The magnitude of the gravitational force between two objects is given by:

where
F is the force
G is the gravitational constant
are the masses of the two objects
is the separation between the objects
We know that:
- The units of F are Newtons (N)
- The units of
are kilograms (kg) - The units of
are metres (m)
So, we can rewrite the equation in terms of G, to find its units:
![G=\frac{Fr^2}{m_1 m_2}=\frac{[N][m]^2}{[kg][kg]}=[N][m^2][kg^{-2}]](https://tex.z-dn.net/?f=G%3D%5Cfrac%7BFr%5E2%7D%7Bm_1%20m_2%7D%3D%5Cfrac%7B%5BN%5D%5Bm%5D%5E2%7D%7B%5Bkg%5D%5Bkg%5D%7D%3D%5BN%5D%5Bm%5E2%5D%5Bkg%5E%7B-2%7D%5D)
Learn more about gravitational force:
brainly.com/question/1724648
brainly.com/question/12785992
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