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2 years ago

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What is KiloWatt unit in simple words?? Explain.......

1 answer:

lbvjy [14]2 years ago

5 0

Answer:

A kilowatt (kW) is 1000 watts. A watt-hour (Wh) is a unit that measures the amount of electrical energy used over a period of time. A kilowatt hour (kWh) is 1000 watt-hours. A kilowatt is a unit of energy that carries a lot of significance in everyday life — it's the base unit used in the routine measurement for electrical energy. All the appliances and gadgets in your home consume electricity measured in kilowatts.

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Determine the displacement of a plane that is uniformly accelerated from 66 m/s to 88 m/s in 12 sec

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2 years ago

In a lab experiment, a student is trying to apply the conservation of momentum. Two identical balls, each with a mass of 1.0 kg,

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Answer:

Second Trial satisfy principle of conservation of momentum

Explanation:

Given mass of ball A and ball B $=\ 1.0\ Kg.$

Let mass of ball $A$ and $B\ is\ m$

Final velocity of ball $A\ is\ v_1$

Final velocity of ball $B\ is\ v_2$

initial velocity of ball $A\ is\ u_1$

Initial velocity of ball $B\ is\ u_2$

Momentum after collision $=mv_1+mv_2$

Momentum before collision $= mu_1+mu_2$

Conservation of momentum in a closed system states that, moment before collision should be equal to moment after collision.

Now, $mu_1+mu_2=mv_1+mv_2$

Plugging each trial in this equation we get,

First Trial

$mu_1+mu_2=mv_1+mv_2\\1(1)+1(-2)=1(-2)+1(-1)\\1-2=-2-1\\-1=-3$

momentum before collision $\neq$ moment after collision

Second Trial

$mu_1+mu_2=mv_1+mv_2\\1(.5)+1(-1.5)=1(-.5)+1(-.5)\\.5-1.5=-.5-.5\\-1=-1$

moment before collision $=$ moment after collision

Third Trial

$mu_1+mu_2=mv_1+mv_2\\1(2)+1(1)=1(1)+1(-2)\\2+1=1-2\\3=-1$

momentum before collision $\neq$ moment after collision

Fourth Trial

$mu_1+mu_2=mv_1+mv_2\\1(.5)+1(-1)=1(1.5)+1(-1.5)\\.5-1=1.5-1.5\\-.5=0$

momentum before collision $\neq$ moment after collision

We can see only Trial- 2 shows the conservation of momentum in a closed system.

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3 years ago

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How can you drop two eggs the fewest amount of times, without them breaking?

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Answer:

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2 years ago

calculate the force required to take away a flat corcular plate of radius 0.01m from the surface of water. the surface tention o

leonid [27]

Answer:

$Force = 0.0047175\ N$

Explanation:

Given

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$r = 0.01m$ --- Radius

Required

Determine the required force

First, we calculate the circumference (C) of the circular plate

$C= 2\pi r$

$C= 2 * \frac{22}{7} * 0.01m$

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The applied force is then calculated using;

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$Force = 0.0047175\ N$

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2 years ago