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4 years ago

Do all ratios compare a part to a whole number? Explain

1 answer:

4 0

Yes and no...

A ratio can be defined in a new ways. Let's say I have a party with twelve people, four of whom are male and eight of whom are female. The ratio of male to female guests would be written as 4:8, neither of which is the whole number (12) but which instead relate parts of the whole. I could alternatively write the ratio of male guests to total guests as 4/12. This does compare it to the whole. A ratio relates two quantities by showing how many times one quantity is contained within or contains another quantity.

By the phrasing of your question, I'm not sure if you maybe mean whole number as an integer. If that's the case, then yes, ratios are almost always written as integers. If I had something like 8.5:7, I would multiply it by two to get 17:14, which is a correct ratio.

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3 years ago

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A school authority claims that the average height of students is 178 cm. A researcher has taken a well-designed survey and his s

Hunter-Best [27]

Answer:

d) The difference exists due to chance since the test statistic is small

Step-by-step explanation:

From the given information:

Population mean = 178 cm

the sample mean = 177.5 cm

the standard deviation = 2

the sample size = 25

The null hypothesis and the alternative hypothesis can be computed as:

Null hypothesis:

$H_o: \mu = 178$

Alternative hypothesis:

$H_1: \mu \neq 178$

The t-test statistics is determined by using the formula:

$t = \dfrac{X - \mu}{\dfrac{\sigma}{\sqrt{n}}}$

$t = \dfrac{177.5 - 178}{\dfrac{2}{\sqrt{25}}}$

$t = \dfrac{-0.5}{\dfrac{2}{5}}}$

$\mathbf{t= -1.25}$

Degree of freedom df = n- 1

Degree of freedom df = 25 - 1

Degree of freedom df = 24

At the level of significance ∝ = 0.05, the critical value = 2.064

Decision rule: To reject the null hypothesis if the test statistics is greater than the critical value at 0.05 level of significance

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3 years ago

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3 years ago

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g Students conducted a survey and found out that 36% of their peers on campus had tattoos but only 4% of their peers were smoker

IgorC [24]

Answer:

D) No, because either np or n(1−p) are less than 15.

Step-by-step explanation:

Percentage of students who had tattoos = 36%

Percentage of students who were smokers = 4%

Sample size = n = 100

The condition to use the Normal distribution as an approximation to construct the confidence interval for population proportion is:

Both np and n(1-p) must be equal to or greater than 15.

Since, we are interested in smokers only, so p = 4% = 0.04

np = 100 x 0.04 = 4

n (1 - p) = 100 x 0.96 = 96

Since, np < 15, we cannot use the Normal distribution as an approximation here.

Therefore, the correct answer is:

No, because either np or n(1−p) are less than 15.

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3 years ago