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3 years ago

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Chemistry

1 answer:

mariarad [96]3 years ago

3 0

The balanced reaction is 3 Ca ( s ) + N 2 ( g ) → Ca 3 N 2 ( s ).

Explanation:

A chemical equation is said to be balanced when the total number of atoms present on the reactants side is equal to the total number of atoms present on the product side.

The unbalanced chemical equation is as follows,

Ca ( s ) + N 2 ( g ) → Ca 3 N 2 ( s )

To balance this equation, you need to look at how many atoms of each element are present on each side of the chemical equation.

Calcium has 1 atom on the reactant and 3 on the products side. To balance the reaction we need to multiply the calcium atom by 3 on the reactants side.

3 Ca ( s ) + N 2 ( g ) → Ca 3 N 2 ( s )

Now Nitrogen has a coefficient of 2 on both sides of the reaction. Hence the balanced chemical equation will thus be

3 Ca ( s ) + N 2 ( g ) → Ca 3 N 2 ( s )

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Given the E0 values of the following two half-reactions: Zn  Zn2+ + 2e- E0 = 0.763 volt Fe  Fe2+ + 2e- E0 = 0.441 volt a) Writ

34kurt

Answer:

For a: The balanced chemical equation is written below.

For b: The corrosion of iron pipe will take place in the presence of zinc.

For c: Zinc will not protect iron pipe from corrosion.

Explanation:

For a:

The given half reaction follows:

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, zinc will undergo reduction reaction will get reduced.

Oxidation half reaction: $Zn\rightarrow Zn^{2+}+2e^-;E^o_{Zn^{2+}/Zn}=-0.763V$

Reduction half reaction: $Fe+2e^-\rightarrow Fe;E^o_{Fe^{2+}/Fe}=-0.441V$

The balanced chemical equation follows:

$Fe+Zn^{2+}\rightarrow Fe^{2+}+Zn$

For b:

For a reaction to be spontaneous (thermodynamically feasible) , the standard electrode potential must be positive.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Calculating the $E^o_{cell}$ using above equation, we get:

$E^o_{cell}=-0.441-(-0.763)=0.322V$

As, the EMF is coming out to be positive, the reaction will be thermodynamically feasible and corrosion of iron pipe will take place in the presence of zinc.

For c:

As, the EMF of the cell is positive, the zinc will not protect the iron pipe from corrosion and the reaction will take place.

4 0

3 years ago

What does refractometer measure?

uranmaximum [27]

A refractometer is an instrument used to measure the refractive index of gases, liquids, and translucent solids like gemstones. Liquids are tested for things such as blood proteins, salinity, fluid concentrations, and specific gravity of urine.

4 0

3 years ago

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Which of the following laboratory procedures best illustrates the law of conservation of mass?

fomenos

The laboratory procedure that best illustrate the law of conservation is

heating 100 g of CaCo3 to produce 56 g of CaO (answer C)

explanation

According to the law of mass conservation , the mass of the reactant must be equal to the mass of the product.

According to option c Heating 100 g CaCO3 to produces 56 g CaO ( 40 +16=56)

The remaining mass = 100-56 = 44 which would the mass of CO2 [ 12 + (16 x2)]= 44 since CaCO3 decomposes to produce CaO and CO2

Therefore the mass of reactant= 100g

mass of product = 56 g +44 g =100

Therefore the laboratory procedure for decomposition of CaCO3 illustrate the law of mass conservation since the mass of reactant = mass of product.

4 0

3 years ago

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There are two different compounds of sulfur and fluorine.

weqwewe [10]

Atomic mass of F: 19.0 g/mol

Atomic mass of S: 32.1 g/mol

1.18 g F = [1.18 g / 19.0 g / mol] = 0.062 mol F

1 g S = 1 g/ 32.1 g/mol = 0.031 mol S

Divide by 0.031

0.062 mol F / 0.031 = 2 mol F

0.031 mol S / 0.031 = 1 mol S

SF2 Then X = 2

Verification:
F2 = 2*19.0 g = 38 g F
S = 32.1 g

36 gF / 32.1 g S = 1.18 g F / g S

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3 years ago

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My name is Ann [436]

D. The final substance in Beaker A is a mixture and in Beaker B is a pure substance.

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