Answer:
209.8 kilo Joules heat is required to vaporize 250 g of ethanol at 78.5 °C.
Explanation:
Mass of an ethanol = 250 g
Molar mass of ethanol = 46 g/mol
Moles of an ethanol = 
Enthalpy of vaporization of ethanol = 
Heat required to vaporize 250 g of ethanol at 78.5 °C : Q


Q = 209.8 kilo Joules
The answer of this question is D
Answer: The net ionic equation for the cobalt-silver voltaic cell is 
Explanation: In cobalt-silver voltaic cell, one half of the cell consists of cobalt electrode immersed in
solution ( which means that
are present in the solution) and other half of the cell consists of the Ag electrode immersed in
solution ( which means that
is present in the solution)
The two electrodes are joined by the copper wire. The cobalt electrode acts as an anode and the silver electrode acts a cathode.
At anode, oxidation reaction takes place and at cathode, reduction reaction takes place.
At Anode : 
At Cathode: ![[Ag^+(aq.)+e^-\rightarrow Ag(s)]\times 3](https://tex.z-dn.net/?f=%5BAg%5E%2B%28aq.%29%2Be%5E-%5Crightarrow%20Ag%28s%29%5D%5Ctimes%203)
Net ionic equation: 
Answer:
10.76 grams
Explanation:
Given that the amount of
is 25.0 grams.
Mass of 1 mole of
= 158 grams
The number of atoms in 1 mole of
is 4.
Mass of oxygen in 1 mole of
= 16\times 4 = 68 grams.
Here, 158 grams of
has 68 grams of oxygen
So, the amount of oxygen in 1 gram of
= 68/158 grams
Therefore, the amount of oxygen in 1 gram of
=
grams
=10.76 grams
Hence, 25 grams of
has 10.76 grams of oxygen.
Answer:
B no observation pls mark me branilest