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leva [86]
3 years ago
10

A poster is 8 1/2 inches by 11 inches you enlarge the poster by increasing each dimension by a factor of 2 1/2 what is the area

of the new poster
Mathematics
2 answers:
Olenka [21]3 years ago
7 0
You have to multiply each side by 2.5 then multiply the two new sides to get the answer. So 8 1/2, which is 8.5 is going to become 21.25 and 11*2.5 is going to become 27.50. So the new dimensions are 21.25 and 27.50, you multiply both of them which would give you an area of 584.375. YOU'RE WELCOME :)
Naya [18.7K]3 years ago
7 0

Answer:

Area of the new poster = 584.375 inch²

Step-by-step explanation:

Length of old poster = 8 1/2 inches = 8.5 inches

Breadth of old poster = 11 inches

Scale factor = 2 1/2 = 2.5

Length of new poster =  8.5 x 2.5 = 21.25 inch

Breadth of new poster =  11 x 2.5 = 27.5 inch

Area of new poster = 21.25 x 27.5 = 584.375 inch²

Area of the new poster = 584.375 inch²

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Round 14.603 round to the nearest hundredth
Studentka2010 [4]

Answer:

I believe its 14.60

Step-by-step explanation:


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3 years ago
Adding unlike fractions<br><br> 1/15+38/100
Daniel [21]

Answer:

134/300 or 67/150

Step-by-step explanation:

the LCM of 15 and 100 is 300. 15 *20 is 300 so we multiply both the numerator and denominator of 1/15 by 20 to get 20/300, with 38/100 we multiply by 3 to get 114/300. Now we add 20/300 and 114/300 to get 134/300 which has a common factor of 2 so we can simply it to 67/150

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3 years ago
Angle 2 is 2x+10 angle 4 is 4x+80 solve for x
Airida [17]

Answer:

15

Step-by-step explanation:

Angle 2 is 2x+10

angle 4 is 4x+80

and from the figure we can understand that when we add these 2 equations

We get

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6x= 90

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7 0
2 years ago
Tacoma's population in 2000 was about 200 thousand, and had been growing by about 9% each year. a. Write a recursive formula for
KIM [24]

Answer:

a) The recurrence formula is P_n = \frac{109}{100}P_{n-1}.

b) The general formula for the population of Tacoma is

P_n = \left(\frac{109}{100}\right)^nP_{0}.

c) In 2016 the approximate population of Tacoma will be 794062 people.

d) The population of Tacoma should exceed the 400000 people by the year 2009.

Step-by-step explanation:

a) We have the population in the year 2000, which is 200 000 people. Let us write P_0 = 200 000. For the population in 2001 we will use P_1, for the population in 2002 we will use P_2, and so on.

In the following year, 2001, the population grow 9% with respect to the previous year. This means that P_0 is equal to P_1 plus 9% of the population of 2000. Notice that this can be written as

P_1 = P_0 + (9/100)*P_0 = \left(1-\frac{9}{100}\right)P_0 = \frac{109}{100}P_0.

In 2002, we will have the population of 2001, P_1, plus the 9% of P_1. This is

P_2 = P_1 + (9/100)*P_1 = \left(1-\frac{9}{100}\right)P_1 = \frac{109}{100}P_1.

So, it is not difficult to notice that the general recurrence is

P_n = \frac{109}{100}P_{n-1}.

b) In the previous formula we only need to substitute the expression for P_{n-1}:

P_{n-1} = \frac{109}{100}P_{n-2}.

Then,

P_n = \left(\frac{109}{100}\right)^2P_{n-2}.

Repeating the procedure for P_{n-3} we get

P_n = \left(\frac{109}{100}\right)^3P_{n-3}.

But we can do the same operation n times, so

P_n = \left(\frac{109}{100}\right)^nP_{0}.

c) Recall the notation we have used:

P_{0} for 2000, P_{1} for 2001, P_{2} for 2002, and so on. Then, 2016 is P_{16}. So, in order to obtain the approximate population of Tacoma in 2016 is

P_{16} = \left(\frac{109}{100}\right)^{16}P_{0} = (1.09)^{16}P_0 = 3.97\cdot 200000 \approx 794062

d) In this case we want to know when P_n>400000, which is equivalent to

(1.09)^{n}P_0>400000.

Substituting the value of P_0, we get

(1.09)^{n}200000>400000.

Simplifying the expression:

(1.09)^{n}>2.

So, we need to find the value of n such that the above inequality holds.

The easiest way to do this is take logarithm in both hands. Then,

n\ln(1.09)>\ln 2.

So, n>\frac{\ln 2}{\ln(1.09)} = 8.04323172693.

So, the population of Tacoma should exceed the 400 000 by the year 2009.

8 0
3 years ago
Read 2 more answers
Plss tell me the ans​
brilliants [131]

Answer:

I dont know if this is right but I think its 125/343

4 0
3 years ago
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