Question

4. Calculate the number of liters of oxygen gas needed to produce 15.0 liters of dinitrogen trioxide. Assume all gases are at the same conditions of temperature and pressure.
2N2(g) + 3O2(g)  2N2O3(g)

Answer 1

Answer:

22.5L

Explanation:

Given parameters:

Volume of N₂O₃  = 15liters

Unknown:

volume of oxygen gas  = ?

Solution:

To solve this problem, we need to work from the known to unknown. The known is N₂O₃. We can find the number of moles from here.

Note: The condition is Standard temperature and pressure

   Number of moles  = $\frac{volume }{22.4}$

    Number of moles of N₂O₃ = $\frac{15}{22.4}$   = 0.67moles

The equation of the reaction;

                            2N₂  +  3O₂   →   2N₂O₃

Since the equation is balanced;

                      2 moles of N₂O₃ is produced from 3 moles of O₂

                  0.67moles  of N₂O₃ is produced from $\frac{0.67 x 3}{2}$   = 1.01 moles of O₂

Therefore;

               Volume of O₂   = 1.01 x 22.4  = 22.5L