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Pie
3 years ago
11

4. Calculate the number of liters of oxygen gas needed to produce 15.0 liters of dinitrogen trioxide. Assume all gases are at th

e same conditions of temperature and pressure.
2N2(g) + 3O2(g)  2N2O3(g)
Chemistry
1 answer:
ipn [44]3 years ago
7 0

Answer:

22.5L

Explanation:

Given parameters:

Volume of N₂O₃  = 15liters

Unknown:

volume of oxygen gas  = ?

Solution:

To solve this problem, we need to work from the known to unknown. The known is N₂O₃. We can find the number of moles from here.

Note: The condition is Standard temperature and pressure

   Number of moles  = \frac{volume }{22.4}

    Number of moles of N₂O₃ = \frac{15}{22.4}   = 0.67moles

The equation of the reaction;

                            2N₂  +  3O₂   →   2N₂O₃

Since the equation is balanced;

                      2 moles of N₂O₃ is produced from 3 moles of O₂

                  0.67moles  of N₂O₃ is produced from \frac{0.67 x 3}{2}   = 1.01 moles of O₂

Therefore;

               Volume of O₂   = 1.01 x 22.4  = 22.5L

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Answer: Rate law=k[A]^1[B]^2, order with respect to A is 1, order with respect to B is 2 and total order is 3. Rate law constant is 3L^2mol^{-2}s^{-1}

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From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (2)

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4=2^y,2^2=2^y therefore y=2.

b) From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (3)

From trial 3: 9.6\times 10^{-2}=k[0.20]^x[0.40]^y   (4)

Dividing 4 by 3:\frac{9.6\times 10^{-2}}{4.8\times 10^{-2}}=\frac{k[0.20]^x[0.40]^y}{k[0.10]^x[0.40]^y}

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Thus rate law is Rate=k[A]^1[B]^2

Thus order with respect to A is 1 , order with respect to B is 2 and total order is 1+2=3.

c) For calculating k:

Using trial 1:  1.2\times 10^{-2}=k[0.10]^1[0.20]^2

k=3 L^2mol^{-2}s^{-1}.



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Explanation:

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