pH of the solution after 24. 00 ml of the hcl has been added is 12.87
millimoles NaOH = mL x M = 24.00 mL x 0.25 M = 6.00
millimoles HCl = 24.00 mL x 0.10 M = 2.40
total volume = 48.00 mL
.................................NaOH + HCl ==>NaCl + H2O
initial.........................6.00.........0............0.........0
added.....................................2.40............................
change.................... -2.40......-2.40.........+2.40.... +2.40
equilibrium.................3.60.........0..............2.40.......2.40
The NaCl contributes nothing to the pH of the final solution. The pH is determined by the excess of NaOH present. (NaOH) = millimoles/mL = 3.60/48.00 = 0.075 M = (OH^-)
pOH = -log (OH^-). Then
pOH = -log (0.075)
pOH =1.1249
As we know,
pH + pOH = pKw = 14.00
pH=14-pOH
pH=14-1.1249
pH=12.87
<h3>
What is pH?</h3>
pH is a logarithmic measure of an aqueous solution's hydrogen ion concentration. pH = -log[H+], where log is the base 10 logarithm and [H+] is the concentration of hydrogen ions in moles per liter.
The pH of an aqueous solution describes how acidic or basic it is, with a pH less than 7 being acidic and a pH greater than 7 being basic. A pH of 7 is regarded as neutral (e.g., pure water). pH values typically range from 0 to 14, though very strong acids may have a negative pH and very strong bases may have a pH greater than 14.
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Answer:the ability to be dissolved, especially in water.
Explanation:
Answer:
Option 4. 14.8 g
Explanation:
3NO2 + H2O → 2HNO3 + NO
First let us calculate the molar mass of NO2 and NO. This is illustrated below;
Molar Mass of NO2 = 14 + (2x16) = 14 + 32 = 46g/mol
Mass of NO2 from the question = 3 x 46 = 138g.
Molar Mass of NO = 14 +16 = 30g/mol
From the equation,
138g of NO2 reacted to produce 30g of NO
Therefore, 68.2g of NO2 will react to produce = (68.2 x 30)/138 = 14.8g of NO.