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kiruha [24]
3 years ago
15

When 25.0 mL of sulfuric acid solution was completely neutralized in a titration with 0.05 M NaOH solution, it took 18.3 mL of t

he NaOH(aq) to complete the job. The reaction is:
NaOH(aq) + H2SO4(aq) → Na2SO4(aq) + H2O(l)
What was the molarity of the sulfuric acid solution?
Chemistry
1 answer:
ladessa [460]3 years ago
8 0
Balanced equation will be as follows

2NaOH + H2SO4=Na2SO4 + 2H2O
from MaVa/MbVb=Na/Nb    where Ma is molarity of acid=?
                                                   Va is volume of acid=25.0 mL
                                                   Mb is molarity of base= 0.05 M
                                                   Vb is volume of base=18.3 mL
                                                    Nb number of moles of base= 2
                                                     Na is number of moles of acid =1

Ma*25 mL / 18.3mL*0.05M = 1/2
Ma=18.3*0.05M / 50 = 0.0183M


The molarity of sulphuric acid = 0.0183M

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Answer:

Mass ratio of sulfur and oxygen in compounds A and B is 3:2 which confirms that the mass ratios in the two compounds are simple multiples of each other

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This question seeks to establish/confirm the law of multiple proportions which  posits that elements combine to form different substances which are whole number multiples of each other. Best example of this plays out in the formation of several oxides of the same element. Looking at the ratio in which the elements combine in each of the oxides, we can assume that these ratios are simple whole number multiples of each other.

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