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ss7ja [257]
3 years ago
8

The density of a 13.2 mass solution of naf is

Chemistry
1 answer:
denis23 [38]3 years ago
0 0
The question, as presented, is incomplete. The entire question is shown below:

"<span>The density of a 13.2 mass % solution of NaF is 1.21 g/mL. Find the molarity of the solution."

We are asked to find the molarity of this solution, and molarity is defined as the amount of moles of a compound per unit volume, typically in units of mol/L.

The density of the NaF solution is 1.21 g/mL. Let's take a 1 L sample of this solution and determine the mass.

1.21 g/mL x 1000 mL = 1210 g of solution.

We are told that this solution is 13.2% NaF by mass. So the mass of NaF in this solution is:

1210 x 0.132 = 160 g NaF

We can then turn this mass of NaF into moles of NaF using the molecular weight of 42 g/mol.

160 g NaF / 42 g/mol = 3.80 moles NaF.

Now to convert this into molarity, we simply divide the amount of moles by the volume of sample, in this case 1L:

3.80 moles NaF/ 1L = 3.80 mol/L NaF or 3.80 M NaF.

The molarity is 3.80 M NaF.</span>
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The atmospheric pressure in Francisco on ascertain day was 97.6kpa what was the pressure on mmhg
vodka [1.7K]

Answer:

732.0601 mmHg

Explanation:

Given data:

Pressure = 97.6 KPa

Given pressure in mmHg = ?

Solution:

Kilo pascal and millimeter mercury both are units of pressure.

Kilo pascal is denoted as "KPa"

Millimeter mercury is denoted as " mmHg"

Kilo pascal is measure of force per unit area while also define as newton per meter square.

It is manometric unit of pressure. It is the pressure generated by column of mercury one millimeter high.

Conversation of kilopascal to mmHg:

97.6 × 7.501 = 732.0601 mmHg

3 0
3 years ago
One office building contains only incandescent lights. The building next door contains only fluorescent lights. Predict which bu
denpristay [2]
The building with incandescent light bulbs would have higher energy bills because less than 10% of the bulb is used for light while the rest is given off as heat. Fluorescent light bulbs use ¼ as much energy and provide the same amount of light.
7 0
3 years ago
A geological sample is found to have a Pb-206/U-238 mass ratio of 0.337/1.00. Assuming there was no Pb-206 present when the samp
azamat

Answer:

Age=2.52*10^9 years

Explanation:

To determine the age, we need to know how much U have become Pb, so first we have to calculate the Pb moles present in a sample:

n_{Pb}=\frac{0.337g}{206g/mol}=0.00164 mol

n_{U}=\frac{1 g}{238g/mol}=0.0042 mol

The percentage of U degradation:

P=\frac{n_{Pb}}{n_{Pb}+n_{U}}

P=\frac{0.00164}{0.00164+0.0042}=0.28

Assuming that the life time is linear:

Age=\frac{4.5*10^9 years}{0.5 life time}*0.28 life time

Age=2.52*10^9 years

4 0
3 years ago
Read 2 more answers
Please with this problem
olasank [31]
<h3>Answer:</h3>

            Empirical Formula  =  C₃H₈O₃

            Molecular Formula  =  C₃H₈O₃

<h3>Solution:</h3>

Data Given:

                      Mass of Sample  =  9.2 g

                      Mass of Carbon  =  3.6 g

                      Mass of Hydrogen  =  0.8 g

                      Mass of Oxygen  =  9.2 - (3.6 + 0.8) = 4.8 g

Step 1: Calculate Moles of each Element;

                      Moles of C  =  Mass of C ÷ At.Mass of C

                      Moles of C  = 3.6 ÷ 12.01

                      Moles of C  =  0.2997 mol


                      Moles of H  =  Mass of H ÷ At.Mass of H

                      Moles of H  = 0.8 ÷ 1.01

                      Moles of H  =  0.7920 mol


                      Moles of O  =  Mass of O ÷ At.Mass of O

                      Moles of O  = 4.8 ÷ 16.0

                      Moles of O  =  0.3000 mol

Step 2: Find out mole ratio and simplify it;

                C                                        H                                     O

            0.2997                              0.7920                           0.3000

    0.2997/0.2997                  0.7920/0.2997              0.3000/0.2997

               1                                      2.64                                    1.001

Multiply by 3,

               3                               7.92 ≈ 8                                    3

Hence,  Empirical Formula  =  C₃H₈O₃

Step 3: Calculating Molecular Formula:

Molecular formula is calculated by using following formula,

                    Molecular Formula  =  n × Empirical Formula  ---- (1)

Also, n is given as,

                     n  =  Molecular Weight / Empirical Formula Weight

Molecular Weight  =  92 g.mol⁻¹

Empirical Formula Weight  =  12 (C₃) + 1.01 (H₈) + 16 (O₃)  =  92.08 g.mol⁻¹

So,

                     n  =  92 g.mol⁻¹ ÷ 92 g.mol⁻¹

                     n  =  1

Putting Empirical Formula and value of "n" in equation 1,

                    Molecular Formula  = 1 × C₃H₈O₃

                    Molecular Formula  =  C₃H₈O₃

7 0
2 years ago
A 16.9 gram sample of KCl is used to mak a 250 mL KCl solution. What is the molarity of the KCl solution?
Genrish500 [490]

Answer:

0.906 gm/l

Explanation:

We know that molarity of the a solution is given by,

M= \frac{w}{m} \times \frac{1000}{v}, where 'M' is the molarity, 'w' is the weight of the sample, 'm' is the molar mass, and 'v' is the volume of the solution.

Molarity of a solution tells us the concentration of the solute in the solvent.

Molar mass of KCl is = 74.55

Putting the values we get,

M = \frac{16.9}{74.55} \times \frac{1000}{250}=0.906 gm/l

So the molarity of KCl solution is 0.906 gm/l.

5 0
2 years ago
Read 2 more answers
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