Answer:
t = 0.33h = 1200s
x = 18.33 km
Explanation:
If the origin of coordinates is at the second car, you can write the following equations for both cars:
car 1:
(1)
xo = 10 km
v1 = 55km/h
car 2:
(2)
v2 = 85km/h
For a specific value of time t the positions of both cars are equal, that is, x=x'. You equal equations (1) and (2) and solve for t:
The position in which both cars coincides is:
If the speed of the magnet is doubled, the induced voltage is twice as great
Faraday's law of induction states that whenever relative motion exists between a coil and magnetic field, a voltage will induce in the circuit and this voltage is proportional to the rate of change of the flux. The expression for the motional emf is as follows:
ε=Blv
Here, ε is the motional emf, B is the magnetic field, l is the length of the conductor, and v is the velocity at which the magnetic field changes.
The induced voltage by the moving magnet is directly proportional to the speed of the magnet. Therefore, an increase in the speed of the magnet will increase the induced voltage.
If the speed of the magnet is doubled, the induced voltage is twice as great
Find out more at: brainly.com/question/13369951
In air, you'd call it air resistance, pilots call it drag. In water, some call it
water resistance, or just plain drag.
Whatever it's called, it's the friction between the object and the fluid, plus
the force needed to push the fluid out of the way to let the object get through.
I think the correct answer from the choices listed above is the last option. It is through radiation that energy can travel through empty space. It is only through the radiation type of heat transfer that any medium is not needed for transfer. It can transfer in a vacuum. Hope this answers the question.
Answer:
50°
Explanation:
The tension in the rope fastened to the ceiling has horizontal component 59cosθ and its vertical component is 59sinθ. For equilibrium,
59cosθ = 38 N (the tension in the rope attached to the wall) (1)and
59sinθ = Mg (the weight of the block of mass) (2)
Dividing (2) by (1)
59sinθ/59cosθ = Mg/38
tanθ = Mg/38
θ = tan⁻¹(Mg/38)
Also squaring (1) and (2) and adding
(59cosθ)² = 38² N
(59sinθ)² = (Mg)²
(59cosθ)² + (59sinθ)² = 38² + (Mg)²
59²((cosθ)² + (sinθ)²) = 38² + (Mg)² . Since (cosθ)² + (sinθ)² = 1
59² = 38² + (Mg)²
Mg = √(59² - 38²) = √(3481 - 1444) = √2037 = 45.13 N
θ = tan⁻¹(Mg/38) = tan⁻¹(45.13/38) = tan⁻¹(1.1877) = 49.9° ≅ 50°