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Y_Kistochka [10]
3 years ago
5

Need help with this question

Physics
1 answer:
Ainat [17]3 years ago
5 0
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PLZ ANSWER ASAP
Illusion [34]

Answer:

Option D

48 N

Explanation:

From Newton's law of motion we deduce that the magnitude of force is a product of mass and acceleration hence expressed as, F=ma where F is the magnitude of force, m is the mass of the object and a is the acceleration of the cart. Substituting 24 kg for m and 2 for acceleration then

F=24*2= 48 N

5 0
3 years ago
A rock is thrown horizontally at 10.0m/s off of a 150m sheer cliff. What is the range?
inn [45]

Answer:20

Explanation:

7 0
3 years ago
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A group of scientists have obtained some experimental results.
topjm [15]
<span>In order best to find out whether the obtained experimental results are worth mor etime and resources the group of scientists should present their results (could be done also in poster session) to other scientists in order to hear their opinion and get a feedback. The shoudl also ask another researchers to redo the experiments and to compare the results. </span>
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3 years ago
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How do you do this question? Please include free body diagrams and clear explanation, so I can understand.
vagabundo [1.1K]

Explanation:

Draw a free body diagram for each disc.

Disc A has three forces acting on it: 86.5 N up, T₁ down, and Wa down.

∑F = ma

86.5 N − T₁ − Wa = 0

Wa = 86.5 N − T₁

ma × 9.8 m/s² = 86.5 N − 55.6 N

ma = 3.2 kg

Disc B has three forces acting on it: T₁ up, T₂ down, and Wb down.

∑F = ma

T₁ − T₂ − Wb = 0

Wb = T₁ − T₂

mb × 9.8 m/s² = 55.6 N − 36.5 N

mb = 1.9 kg

Disc C has three forces acting on it: T₂ up, T₃ down, and Wc down.

∑F = ma

T₂ − T₃ − Wc = 0

Wc = T₂ − T₃

mc × 9.8 m/s² = 36.5 N − 9.6 N

mc = 2.7 kg

Disc D has two forces acting on it: T₃ up and Wd down.

∑F = ma

T₃ − Wd = 0

Wd = T₃

md × 9.8 m/s² = 9.6 N

md = 0.98 kg

3 0
3 years ago
An object initially at rest experiences an acceleration of 9.8 m/s2. How much time will it take to achieve a velocity of 58 m/s?
frez [133]
5.91(approx) seconds just divide velocity by acceleration
4 0
3 years ago
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