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jenyasd209 [6]
4 years ago
6

NEED ANSWER ASAP!!!!!!

Physics
2 answers:
TiliK225 [7]4 years ago
6 0

Answer:

yes I do it all the time and its smelly

olga55 [171]4 years ago
5 0

Answer:

yes. why do you need this answered asap? lol

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A ball of mass 4.5 kg moving with speed of 2.2 m/s in the +x-direction hits a wall and bounces back with the same speed in the x
Levart [38]

Answer:

The change of the momentum of the ball is -19.8\, \frac{mkg}{s}

Explanation:

We should find \varDelta\overrightarrow{p}=\overrightarrow{p_{f}}-\overrightarrow{p_{i}} (1)with \overrightarrow{p_{i}} the initial momentum and \overrightarrow{p_{f}} the final momentum. Linear momentum is defined as \overrightarrow{p}=m\overrightarrow{v}, using that on (1):

\varDelta\overrightarrow{p}=m \overrightarrow{v_{f}}-m \overrightarrow{v_{i}} (2)

It's important to note that momentum and velocity are vectors and direction matters, so if +x direction is the direction towards the wall and the -x direction away the wall \overrightarrow{v_{i}}=+2.2\, \frac{m}{s} and \overrightarrow{v_{f}}=-2.2\, \frac{m}{s} so (2) becomes:

\varDelta\overrightarrow{p}=m(-2.2- (+2.2))=-(4.5)(4.4)

\varDelta\overrightarrow{p}=-19.8\, \frac{mkg}{s}

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3 years ago
What is my purpose?
castortr0y [4]
As Rene Descartes - french mathematician of Cartesian graphs - said "Cogito ergo sum". I think, therefore I am. 
This can be adapted to I think therefore I am, I think ... as a "geeky joke".
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3 years ago
A 1500 kg car traveling at 15.0 m/s to the south collides with a 4500 kg truck that is at rest at a stopligt. The car comes to a
Arlecino [84]

Answer:

<em><u>M</u></em><em><u>a</u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u>m</u></em><em><u>a</u></em><em><u>t</u></em><em><u>i</u></em><em><u>c</u></em><em><u>a</u></em><em><u>l</u></em><em><u>l</u></em><em><u>y</u></em><em><u>:</u></em>

That will be

<em>=</em><em> </em><em>1</em><em>5</em><em>0</em><em>0</em><em> </em><em>x</em><em> </em><em>1</em><em>5</em><em> </em><em>x</em><em> </em><em>4</em><em>5</em><em>0</em><em>0</em>

<em>=</em><em> </em><em><u>1</u></em><em><u>0</u></em><em><u>1</u></em><em><u>,</u></em><em><u>2</u></em><em><u>5</u></em><em><u>0</u></em><em><u>,</u></em><em><u>0</u></em><em><u>0</u></em><em><u>0</u></em>

5 0
3 years ago
un avión aterriza en la superficie de un portaaviones a 50 m/s y se detiene por completo en 120 metros, ¿cuál es la aceleración
sergejj [24]

Answer:

La aceleración necesaria para detener el avión es - 10.42 m/s².

Explanation:

Un movimiento uniformemente acelerado (M.U.A) es aquél cuya aceleración es constante y la velocidad de un objeto cambia a medida que el movimiento evoluciona.

Siendo la aceleración "a" el cambio de velocidad al tiempo transcurrido en un punto A a B, la velocidad inicial la velocidad que tiene un cuerpo al iniciar su movimiento en un período de tiempo y la velocidad final la velocidad que tiene un cuerpo al finalizar su movimiento en un período de tiempo, entonces en  M.U.A se cumple:

Vf² - Vo² = 2*a*d

donde:

  • Vf: Velocidad final
  • Vo: Velocidad inicial
  • a: Aceleración
  • d: Distancia recorrida

En este  caso:

  • Vf: 0 m/s, porque el avión se detiene
  • Vo: 50 m/s
  • a: ?
  • d: 120 m

Reemplazando:

(0 m/s)² - (50 m/s)² = 2*a*120 m

Resolviendo:

a=\frac{(0 m/s)^{2} -(50 m/s)^{2} }{2*120 m}

a= - 10.42 m/s²

<u><em>La aceleración necesaria para detener el avión es - 10.42 m/s².</em></u>

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Alja [10]

non examples of temperature are dixionanon , fairinheat, cabrowskin, and lastly ancomthere

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