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jenyasd209 [6]
4 years ago
6

NEED ANSWER ASAP!!!!!!

Physics
2 answers:
TiliK225 [7]4 years ago
6 0

Answer:

yes I do it all the time and its smelly

olga55 [171]4 years ago
5 0

Answer:

yes. why do you need this answered asap? lol

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3. What is the mass of a paratrooper who experiences an air resistance of 400 N and an acceleration of 4.5 m/s2
goblinko [34]

Answer:

88.89kg

Explanation:

The formula for mass is m=F/a. If we plug in the values, we get m=400N/4.5m/s^2. The mass is 88.89kg. We know that the unit is in kg because one newton (N) is 1kg*m/s^2. The m/s^2 is cancelled out by the acceleration, and we are left with kg.

4 0
4 years ago
A car travels straight for 20 miles on a road that is 30° north of east. What is the east component of the car’s displacement to
Virty [35]
17.3 would be the correct answer.

4 0
4 years ago
Read 2 more answers
Will Upvote!!!
katrin2010 [14]
The answer is A. Since the car is moving at a constant velocity, the car not accelerate no matter how far it travels.
5 0
3 years ago
A football is kicked into the air from an initial height of 4 feet. The height, in feet, of the football above the ground is giv
kakasveta [241]

Answer: 0.5 seconds or 2.625 seconds

Explanation:

At t = 0, The ball is 4 ft above the ground.

The height of the football varies with time in the following way:

s(t) = -16 t² + 50 t + 4

we need to find the time in which the height would of the football would be 25 ft:

⇒25 = -16 t² + 50 t + 4

we need to solve the quadratic equation:

⇒ 16 t² - 50 t + 21 = 0

t = \frac{50 \pm \sqrt{50^2-4\times 16\times 21}}{2\times16}

⇒ t = 0.5 s or 2.625 s

Therefore, at t = 0.5 s or 2.625 s, the football would be 25 ft above the ground.

3 0
3 years ago
Read 2 more answers
Hi please answer and show your work​
jek_recluse [69]

Answer:

\huge\boxed{\sf P.E. = 240\ MJ}

\huge\boxed{\sf K.E. = 19.6\ MJ}

Explanation:

<u>Given:</u>

Mass = m = 200,000 kg

Vertical Distance = h = 120 m

Speed = v = 14 m/s

Acceleration due to gravity = g = 10 m/s²

<u>Required:</u>

1) Gravitational Potential Energy = P.E = ?

2) Kinetic Energy = K.E. = ?

<u>Formula:</u>

1) P.E. = mgh

2) K.E. = \displaystyle \frac{1}{2} mv^2

<u>Solution:</u>

1) P.E. = (200,000)(10)(120)

P.E. = 240,000,000 Joules

P.E. = 240 Mega Joules

P.E. = 240 MJ

2) K.E. = 1/2 (200000)(14)^2

K.E. = (100000)(196)

K.E. = 19,600,000 Joules

K.E. = 19.6 MJ

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
4 0
3 years ago
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