Answer:
The total voltage of the circuit is 18 volts.
Explanation:
We have, three identical resistors of resistance 3 ohms are connected in series in a circuit.
For a series combination, the equivalent resistance is given by the sum of individual resistances i.e.

Let V is the voltage of the battery if the current in the circuit is 2 A. So,


So, the total voltage of the circuit is 18 volts.
Copper because it contains alot of electricity
For a curved mirror, all points have the same normal and the angle of incidence is also equal to the angle of reflection.
According to the laws of reflection, the incident ray, reflected ray and normal all lie on the same plane. For a curved mirror, the normal remains the same at all points along the curved mirror.
Again, the angle made between the incident ray and the normal is the same as the angle made between the reflected ray and the normal. Therefore, the angle of reflection is equal to the angle of incidence.
Learn more: brainly.com/question/17638582
Answer:
Part a)

Part b)

Part c)

Explanation:
Part a)
As we know that ball will reach at maximum height at
t = 3 s
now we will have

now we have


Now maximum height above ground is given as



Part b)
Height of the fence is given as



Part c)
As we know that its horizontal distance moved by the ball in 5.5 s is given as



now total time of flight is given as

so range is given as



so the distance from the fence is given as


<span>c. What is the magnitude of the tension in the string at the bottom of the circle if you are swinging it at 3.37 m/s?
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