1. I think is letter b.
2. I thinks it's letter c.
Answer:
a) 6.8 Volt
b) 1.21Цm
Explanation:
We are given from the question that
The zero -bias depletion layer width(
) is 0.4Цm
The built in voltage φj is 0.85V
Now to calculate the reverse voltage(
) that would be required to triple the depletion - layer width.
The depletion - layer width (
) of the diode has the formula

For three times of
we have

=> 
=> 
Substituting value of φj
We have

= 6.8 V
The required bias voltage
is 6.8 V
The solution for the b part of the question is uploaded on first image
D)LT^-1 speed=distance(L)/time(T)——>L/T
Explanation:
Given:
m = 1.673 × 10^-27 kg
Q = q = 1.602 × 10^-19 C
r = 0.75 nm
= 0.75 × 10^-9 m
A.
Energy, U = (kQq)/r
Ut = 1/2 mv^2 + 1/2 mv^2
1.673 × 10^-27 × v^2 = (8.99 × 10^9 × (1.602 × 10^-19)^2)/0.75 × 10^-9
v = 1.356 × 10^4 m/s
B.
F = (kQq)/r^2
F = m × a
1.673 × 10^-27 × a = ((8.99 × 10^9 × (1.602 × 10-19)^2)/(0.075 × 10^-9)^2
a = 2.45 × 10^17 m/s^2.
Explanation:
We know that the relation between volume and density is as follows.
Volume = 
So, V = 
= 
Now, we will calculate the area as follows.
Area = 
= 
= 
Formula to calculate the resistance is as follows.
R = 
= 
= 
Thus, we can conclude that the resistance of given wire is
.