Answer:
Yes, the car has acceleration.
Explanation:
Acceleration is defined as the rate of change of velocity. The velocity is a vector quantity. If a car is moving with constant speed but taking a turn, it means the velocity is changing, so the car have some acceleration.
Answer: 1- A diagram showing the forces acting on the object.
2- The force vector describes a specific amount of force and its direction. You need both value and direction to have a vector.
3- A vector quantity has a direction and a magnitude, while a scalar has only a magnitude. You can tell if a quantity is a vector by whether or not it has a direction associated with it.
4- I don’t know
5- When two forces acting on an object are equal in size but act in opposite directions, we say that they are balanced forces
6- By applying an unbalanced force, you can change the motion of an object. Unbalanced forces can make an object at rest start moving, make a moving object stop, or change the direction and speed of the object.
7- If the forces on an object are unbalanced, this is what happens: a stationary object starts to move in the direction of the resultant force.
8- Imbalance or unequal force
9- The result is no motion. Balanced forces can cancel each other out. Any time there is a balanced force, the object does not move.
10- net force is the vector sum of all the forces that act upon an object.
RESTATE THESE
Explanation:
RESTATE!!!!
Answer:
Data:-vi=om/s (b/c as in question penny is dropped from building means before coming to ground its initial state or velocity was considered as zero ) now distance or height h=380m and now we have to find the final velocity vf=? and the time t=?
Explanation:
So applying second eq of motion s=vit+1/2×gt² (here we have taken a gravity b/c when ever body is in vertical position then acceleration due to gravity is applied ) s=0×t+1/2×gt² , s=0+1/2×9.8×t² ,380=4.9t² we have to find t so 4.9t²=380 , t²=380÷4.9 , t²=77.55 now sq root on b/s
so t=8.806s and now apply 1st eq o²f motion to find out vf so vf=vi+gt , vf=0+9.8×8.806 ,vf=86.298 and if you want to verify that either this is answer is correct or not so put the value of t in second eq of motion and if you got distance same as give in the question so your value of t is considered as correct likewise s=vit+1/2gt² , s=0+1/2×9.8(8.806)²,s=4.9×77.55 ,s=380m (proved) I hope it would be helpfull
