Question

A bicycle traveled 150 meters west from point A to point B. Then it took the same route and came back to point A. It took a total of 2 minutes for the bicycle to return to point A. What is the average speed and average velocity of the bicycle?

Answer 1

The average speed is (distance)/(time) = 300m / 2min. That's 150m per minute, or 2.5m per second. The average velocity is (displacement)/(time) = (distance from the start point to the end point regardless of the route)/(time)= zero.

Answer 2

Answer:

The average speed is 1.5 meters per second.

Explanation:

Givens

• Bicycle traveled a distance of 150 meters, twice, from point A to B, and from B to A.
• The time it took to return to point A is 2 minutes, which is 120 seconds.

Basically, the bicycle traveled a total of 300 meters using 4 minutes, assuming that is a constant movement. So, the average speed is

$s=\frac{300m}{4(60sec)}=1.25 m/s$

Therefore, the average speed is 1.5 meters per second.