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Goshia [24]
3 years ago
11

The temperature of a sample gas in a steel tank 30.00 kpa increased from 10.0 c to 25.0c what is the final pressure inside the t

ank?
Chemistry
1 answer:
egoroff_w [7]3 years ago
4 0

Answer:

31.59 kpa

Explanation:

The variables in this problem are temperature and pressure. Both variables are related by the gay lusaacs law.

Gay-Lussac's Law: The Pressure Temperature Law. This law states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature. This means that as the pressure increases so does the temperature.

From the law, we have;

P1/P2 = T1/T2

From the problem;

P1 = Intial pressure = 30 kpa

P2 = Final pressure = x

T1 = Initial temperature = 10 + 273 = 283K (Upon converting to kelvin temperature)

T2 = Final temperature = 25 + 273 = 298K (Upon converting to kelvin temperature)

Substituting into the equation, we have;

30 / P2 = 283 / 298

Upon cross multiplication, we have;

P2 = (298 * 30 ) / 283

P2 = 31.59 kpa

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A serving of soup contains 5.0 g of fat, 20.0 g of carbohydrates, and 3.0 g of protein. Determine how many kilocalories (kcal) a
marta [7]

<u>Answer:</u> The amount of kilocalories contained in the given serving of soup is 0.137 kCal

<u>Explanation:</u>

<u>As per the USDA:</u>

Carbohydrates provide 4 calories per gram, protein provides 4 calories per gram, and fat provides 9 calories per gram.

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Mass of fat in the soup serving = 5.0 g

Mass of carbohydrates in the soup serving = 20.0 g

Mass of protein in the soup serving = 3.0 g

Conversion factor used:  1 kCal = 1000 Cal

Applying unitary method:

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1 gram of fat provides 9 calories

So, 5.0 gram of fat will provide = \frac{9}{1}\times 5.0=45Cal=0.045kCal

  • <u>For Carbohydrates:</u>

1 gram of carbohydrates provides 4 calories

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  • <u>For Proteins:</u>

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Hence, the amount of kilocalories contained in the given serving of soup is 0.137 kCal

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