Answer:
3. 3.45×10¯¹⁸ J.
4. 1.25×10¹⁵ Hz.
Explanation:
3. Determination of the energy of the photon.
Frequency (v) = 5.2×10¹⁵ Hz
Planck's constant (h) = 6.626×10¯³⁴ Js
Energy (E) =?
The energy of the photon can be obtained by using the following formula:
E = hv
E = 6.626×10¯³⁴ × 5.2×10¹⁵
E = 3.45×10¯¹⁸ J
Thus, the energy of the photon is 3.45×10¯¹⁸ J
4. Determination of the frequency of the radiation.
Wavelength (λ) = 2.4×10¯⁵ cm
Velocity (c) = 3×10⁸ m/s
Frequency (v) =?
Next, we shall convert 2.4×10¯⁵ cm to metre (m). This can be obtained as follow:
100 cm = 1 m
Therefore,
2.4×10¯⁵ cm = 2.4×10¯⁵ cm × 1 m /100 cm
2.4×10¯⁵ cm = 2.4×10¯⁷ m
Thus, 2.4×10¯⁵ cm is equivalent to 2.4×10¯⁷ m
Finally, we shall determine the frequency of the radiation by using the following formula as illustrated below:
Wavelength (λ) = 2.4×10¯⁷ m
Velocity (c) = 3×10⁸ m/s
Frequency (v) =?
v = c / λ
v = 3×10⁸ / 2.4×10¯⁷
v = 1.25×10¹⁵ Hz
Thus, the frequency of the radiation is 1.25×10¹⁵ Hz.
Answer:
nah but ill take points tho
Explanation:
The mass of He gas = 21.428 g
<h3>Further explanation</h3>
Given
120 liters of He gas
Required
the mass in grams
Solution
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.
Mol for 120 L :

Mass of He gas(MW=4 g/mol) :

Answer:
Which word in the following sentence is a linking verb?
The gym became noisy when fans stamped and cheered for the home team.
A. became
B. noisy
C. stamped
D. cheered
Which word in the following sentence is a linking verb?
The gym became noisy when fans stamped and cheered for the home team.
A. became
B. noisy
C. stamped
D. cheered
Explanation:
Which word in the following sentence is a linking verb?
The gym became noisy when fans stamped and cheered for the home team.
A. became
B. noisy
C. stamped
D. cheered
Answer:
THE MASS OF THE LIQUID IS 22.5 g
Explanation:
Density = 0.180 g/cm3
Side length = 5 cm
Mass = unknown
To calculate the mass of the liquid, we use the formula:
Mass = density * volume
Volume of a cube or cuboid container = l^3
Volume = 5 ^3 = 125 cm3
So therefore, the mass of the liquid is:
Mass = 0.180 * 125
Mass = 22.5 g
In conclusion, the mass of the liquid in the container is 22.5 g