Answer:
All the statements are correct but "all chemical reactions can be classified as one of the five general types".
Explanation:
Hello,
In this case, I assume you are looking for the wrong statement as long as the following ones are correct and matches with the foundations of chemical reactions:
- The only way to determine the products of a reaction is to carry out the reaction. This is clear, because after the chemical reaction is done, one identifies the products.
- Complete combustion has occurred when all the carbon in the product is in the form of carbon dioxide. This is clear due to a 100% conversion.
- A single reactant is the identifying characteristic of a decomposition reaction. All decomposition reactions have only one reactant which breaks into less complex species.
So the wrong statement is:
- All chemical reactions can be classified as one of five general types. This is wrong because there are four widely known chemical reactions: synthesis, decomposition, simple displacement and double displacement.
Best regards.
what is the answer to what there is nothing here
Answer: The temperature of the gas is 132.25K and -140.75°C
Explanation:
Given that:
Volume of helium gas (V) = 18.5L
Temperature of helium gas (T) = ?
Pressure (P) = 0.85 atm
Number of moles (n) = 1.45 moles
Molar gas constant (R) is a constant with a value of 0.082 atm L K-1 mol-1
Then, apply the formula for ideal gas equation
pV = nRT
0.85atm x 18.5L = 1.45 moles x 0.082 atm L K-1 mol-1 x T
15.725 atm•L = 0.1189 atm•L•K-1 x T
T = 15.725 atm•L / 0.1189 atm•L•K-1
T = 132.25K
Given that temperature in Kelvin is 132.25, convert it to Celsius by subtracting 273
So, T(in Celsius) = 132.25K - 273
= -140.75°C
Thus, the temperature of the gas is 132.25K and -140.75°C
Answer:
Mass of aluminium in sample = 3.591 g ≅ 3.6 grams
Explanation:
Given that, A sample of aluminum absorbs 50.1 J of heat, upon which the temperature of the sample increases from 20.0°C to 35.5°C.
the specific heat of aluminum is 0.900 J/g- °C
The relation between heat absorbed and change in temperature is given by, Q = msΔT.
where Q = heat absorbed
m = mass of the substance
s = specific heat of substance
ΔT = change in temperature
Now, in our case, Q = 50.1 J ; s = 0.900 J/g- °C; ΔT= 35.5-20 = 15.5°C
⇒ m = 
⇒ m = 
= 3.591 g ≅ 3.6 g
⇒ m ≅ 3.6 g
A is your answer................???
