Answer:
D. beginning numbering at the end farther from the first branch.
Explanation:
In naming alkanes, the longest continuous chain in the compound is first considered and this gives the name of the compound intended. The name of the substituent on the compound are also arranged in alphabetical order when naming the compound.
The carbon atoms are numbered in the parent chain or ring to indicate where branching or substitution takes place. The direction of numbering is chosen such that the lowest numbers possible is given to the branches or substituents. If we begin the numbering at the end farther from the first branch, we won't give the lowest numbers possible to the branches.
<span>the empirical formula is C3H8O2
You need to determine the relative number of moles of hydrogen and carbon. So you first calculate the molar mass of CO2 and H20
Atomic weight of carbon = 12.0107
Atomic weight of hydrogen = 1.00794
Atomic weight of oxygen = 15.999
Molar mass CO2 = 12.0107 + 2 * 15.999 = 44.0087
Molar mass H2O = 2 * 1.00794 + 15.999 = 18.01488
Now calculate the number of moles of CO2 and H2O you have
Moles CO2 = 2.086 g / 44.0087 g/mole = 0.0474 mole
Moles H2O = 1.134 g / 18.01488 g/mole = 0.062948 mole
Calculate the number of moles of carbon and hydrogen you have. Since there's 1 carbon atom per CO2 molecule, the number of moles of carbon is the same as the number of moles of CO2. But since there's 2 hydrogen atoms per molecule of H2O, The number of moles of hydrogen is double the number of moles of H2O
Moles Carbon = 0.0474
Moles Hydrogen = 0.062948 * 2 = 0.125896
Now we need to determine how much oxygen is in the compound. Just take the mass of the compound and subtract the mass of carbon and hydrogen. What's left will be the mass of oxygen. Then divide that mass by the atomic weight of oxygen to get the number of moles of oxygen we have.
1.200 - 0.0474 * 12.0107 - 0.125896 * 1.00794 = 0.503797
Moles oxygen = 0.503797 / 15.999 = 0.031489
So now we have a ratio of carbon:hydrogen:oxygen of
0.0474 : 0.125896 : 0.031489
We need to find a ratio of small integers that's close to that ratio. Start by dividing everything by 0.031489 (selected because it's the smallest value) getting
1.505288 : 3.998095 : 1
The 1 for oxygen and the 3.998095 for hydrogen look close enough. But the 1.505288 for carbon doesn't work. But it looks like if we double all the numbers, we'll get something close to an integer for everything. So do so.
3.010575 : 7.996189 : 2
Now this looks good. Rounding everything to an integer gives us
3 : 8 : 2
So the empirical formula is C3H8O2</span>
Single Replacement and Double Replacement reactions
Answer:
E° = -1.66 V
Explanation:
The standard reduction potential is also known as the standard electrode potentials and it tries to find the probability that an element will be reduced or undergo reduction.
From activation series online showing the standard reduction potentials for half cells, the standard reduction potential of Al3+ (aq) + 3e- -> Al(s) is;
E° = -1.66 V
Answer:
B. They all have the same properties.
Explanation:
For example....they contain nucleus in their center.
