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Vikki [24]
4 years ago
10

What property do the following elements have in common? sulfur, iodine, and magnesium A) Same phase at room temperature. B) Good

conductors of electricity. C) Same number of valence electrons. Eliminate D) They form cations (positive ions).
Physics
2 answers:
kolbaska11 [484]4 years ago
7 0
Sulphur (S), Iodine (I) and Magnesium (Mg) are all three, solids at the room temperature. Thus they have the same phase at room temperature. 
Sulphur and Iodine are not good conductors of electricity.
Also while Sulphur is in group 6, Magnesium is in group 2. Therefore they do not have the same number of valence electrons. Sulphur is making anions (negative ions) and Magnesium is making cations (positive ions).
Afina-wow [57]4 years ago
7 0

i just did it and the answer us A

You might be interested in
5. The entrance of a science museum features a funnel into which marbles are rolled one at a time. The marbles circle around the
Katena32 [7]

Answer:

400.7886829 rad/s

Explanation:

First we have to turn our 0.35 rev/s into rad/s using the equation

(Xrev/s)*2pi=Xrad/s we can plug in .35*2pi=.7pi rad/s

Now we can us the equation m_1*v_1*r_1^2=m_1*v_2*r_2^2 we can plug in the given. Because the mass remains the same we can cross it off of both sides giving us just: v_1*r_1^2=v_2*r_2^2

(.7pi)*(.54)^2=(v_2)*(.04)^2

(.20412pi)=(v_2)*(.0016)     [.20412pi=.6412618925]

then using division on both sides we get

(.6412618925/.0016)=v_2=400.79rad/s(This answer is rounded to the nearest hundreth)

See you in Mr.K's class tomorrow! -Ruben

3 0
3 years ago
Rays of light strike a bumpy road and are reflected.
ser-zykov [4K]

Answer:

last option is the correct one

6 0
3 years ago
Read 2 more answers
The age of the solar system is closest to _____ years old.
tester [92]
The age of the solar system is 4,600,000,000
6 0
4 years ago
What are the density, specific gravity and mass of the air in a room whose dimensions are 4 m * 6 m * 8 m at 100 kPa and 25 C.
Volgvan

Answer:

Density = 1.1839 kg/m³

Mass = 227.3088 kg

Specific Gravity = 0.00118746 kg/m³

Explanation:

Room dimensions are 4 m, 6 m & 8 m. Thus, volume = 4 × 6 × 8 = 192 m³

Now, from tables, density of air at 25°C is 1.1839 kg/m³

Now formula for density is;

ρ = mass(m)/volume(v)

Plugging in the relevant values to give;

1.1839 = m/192

m = 227.3088 kg

Formula for specific gravity of air is;

S.G_air = density of air/density of water

From tables, density of water at 25°C is 997 kg/m³

S.G_air = 1.1839/997 = 0.00118746 kg/m³

4 0
3 years ago
A 63-kg hiker is climbing the 828-m-tall Burj Khalifa in Dubai. If the efficiency of converting the energy content of the bars i
konstantin123 [22]

Answer:

T_f=5854.76 °C

Explanation:

Given:

mass of hiker, m= 63 kg

height to be climbed, h= 828 m

energy produced by an energy bar, E= 1.10\times 10^6 J

heat capacity of the hiker, c=75.3 J.mol^{-1}.K^{-1}= 4.184 J.kg^{-1}.K^{-1}

initial body temperature of hiker, T_i=36.6 \degree C

<em>The efficiency of converting the energy content of the bars into the work of climbing is 25%, the remaining 75% of the energy released through metabolism is heat released to her body.</em>

We find the energy required for climbing 828 m height:

W=m.g.h

W=63\times 9.8\times 828

W= 511207.2 J

∵Hike eats 2 energy bars= 2\times 1.1\times 10^{6} J

Energy produced= 2.2\times 10^{6} J

Now, according to her efficiency:

Total energy required for producing the work of W= 511207.2 J which is required to climb the given height will be (say, E):

25\% of E= 511207.2

\Rightarrow E= 511207.2\times \frac{100}{25}

E=2044828.8 J

&

Amount of total energy (E) converted into heat(Q) is:

Q=2044828.8-511207.2\\Q=1533621.6J

As we know that:

heat, Q=m.c. (T_f-T_i).................(1)

where:

T_f is the final temperature

Putting respective values in the eq. (1)

1533621.6= 63\times 4.184\times (T_f-36.6)

(T_f-36.6)\approx 5818.16

T_f\approx 5854.76 °C

4 0
3 years ago
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