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Vikki [24]
3 years ago
10

What property do the following elements have in common? sulfur, iodine, and magnesium A) Same phase at room temperature. B) Good

conductors of electricity. C) Same number of valence electrons. Eliminate D) They form cations (positive ions).
Physics
2 answers:
kolbaska11 [484]3 years ago
7 0
Sulphur (S), Iodine (I) and Magnesium (Mg) are all three, solids at the room temperature. Thus they have the same phase at room temperature. 
Sulphur and Iodine are not good conductors of electricity.
Also while Sulphur is in group 6, Magnesium is in group 2. Therefore they do not have the same number of valence electrons. Sulphur is making anions (negative ions) and Magnesium is making cations (positive ions).
Afina-wow [57]3 years ago
7 0

i just did it and the answer us A

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The diagram below shows the structural formula and 3D model of the same substance. Which substance is represented by the diagram
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I feel like its C but mmmm idk
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A yacht is pushed along at a constant velocity by the wind. The wind force is 180N at an angle of 25 degrees to the direction of
damaskus [11]
The parallel component is given by
F=180cos(25)=163.14N
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3 years ago
Who was the first to hypothesize that electron orbit a positively charged nucleus
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3 years ago
A cake is removed from a 350◦F oven and placed on a cooling rack in a 70◦F room. After 30 minutes the cake is 200◦F. When will i
galben [10]

Answer:

350 F to 100 F it take approx 87.33 min  

Explanation:

given data

oven = 350◦F

cooling rack = 70◦F

time = 30 min

cake = 200◦F

solution

we apply here Newtons law of cooling  

\frac{dT}{dt} = -k(T-Ta)

\frac{dy}{dt} = \frac{d}{dt} (T(t) -Ta)

= \frac{dT}{dt} -\frac{dTa}{dt} =\frac{dT}{dt} = -k(T-Ta)

-ky \frac{dy}{dt} = -ky

T(t) -Ta = (To -Ta) e^{-kt} T(t) = Ta+ (To -Ta)  e^{-kt}

put her value for time 30 min and T(t) = 200◦F and To =350◦F  and Ta = 70◦F

so here

200 = 70 + ( 350 - 70 ) e^{-k30}

k = 0.025575

so here for  T(t) = 100F

100 = 70 + ( 350 - 70 ) e^{-0.025575*t}

time = 87.33 min

so here 350 F to 100 F it take approx 87.33 min  

5 0
3 years ago
Illustrate a body of mass 5.0kg pulled by horizontal force F . if the body accelerates 2.0ms² and experience a frictional force
Natasha2012 [34]

Explanation:

a. Net force is mass times acceleration (Newton's second law).

∑F = ma

∑F = (5.0 kg) (2.0 m/s²)

∑F = 10 N

b. The net force is the sum of the individual forces.

10 N = F − 5 N

F = 15 N

c. Friction force here is mgμ.

mgμ = 5 N

(5.0 kg) (10 m/s) μ = 5 N

μ = 0.1

3 0
3 years ago
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