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mestny [16]
3 years ago
13

Which interaction of nature depends on the distance through which it acts and is involved in beta decay? a. strong c. electromag

netic b. weak d. gravitational
Physics
1 answer:
USPshnik [31]3 years ago
5 0

The answer is weak.  The interaction of nature that will depend on the distance through the way it acts and involved in beta decay is the weak interaction or the weak force. This interaction is the responsible for radioactive decay which also plays a significant role in nuclear fission.

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An airplanes lands with a velocity of +75 m/s and comes to a stop in 20 seconds. What is the acceleration of the airplane while
erma4kov [3.2K]

Answer:

The acceleration of the car, a = -3.75 m/s²

Explanation:

Given data,  

The initial velocity of the airplane, u = 75 m/s

The final velocity of the plane, v = 0 m/s

The time period of motion, t = 20 s

Using the I equations of motion

                    v = u + at

                     a = (v - u) / t

                        = (0 - 75) / 20

                        = -3.75 m/s²

The negative sign indicates that the plane is decelerating

Hence, the acceleration of the car, a = -3.75 m/s²

7 0
3 years ago
how much time would it take for an airplane to reach its destination if it traveled at an average speed of 790 km/hr for a dista
NeTakaya
I think your question is incomplete because the distance between destination and departure point isn't given in the question

8 0
3 years ago
A 6.00-kg box sits on a ramp that is inclined at 37.0° above the horizontal. the coefficient of kinetic friction between the box
forsale [732]
We need to see what forces act on the box:

In the x direction:

Fh-Ff-Gsinα=ma, where Fh is the horizontal force that is pulling the box up the incline, Ff is the force of friction, Gsinα is the horizontal component of the gravitational force, m is mass of the box and a is the acceleration of the box.

In the y direction:

N-Gcosα = 0, where N is the force of the ramp and Gcosα is the vertical component of the gravitational force. 

From N-Gcosα=0 we get: 

N=Gcosα, we will need this for the force of friction.

Now to solve for Fh:

Fh=ma + Ff + Gsinα,

Ff=μN=μGcosα, this is the friction force where μ is the coefficient of friction. We put that into the equation for Fh.
G=mg, where m is the mass of the box and g=9.81 m/s²

Fh=ma + μmgcosα+mgsinα

Now we plug in the numbers and get:

Fh=6*3.6 + 0.3*6*9.81*0.8 + 6*9.81*0.6 = 21.6 + 14.1 + 35.3 = 71 N

The horizontal force for pulling the body up the ramp needs to be Fh=71 N.
8 0
3 years ago
A car with a mass of 1500 kg accelerates when the traffic light turns green. If the net force on the car is 3750 newtons, what i
timurjin [86]

Answer:

2.5 ms⁻²

Explanation:

By Newton's 2nd law,

The rate of change of momentum is directly proportional to the unbalance force applied on the object,

By that you can get the equation,

F = ma ⇒ a = F/m

where terms are in usual meaning

a = 3750/1500 = 2.5 ms⁻²

 

8 0
3 years ago
The graph represents the heating of water in a pot. At 150 seconds, the water has just reached a boil. If the heat is left on, w
a_sh-v [17]
The temperature will remain constant, at around 100 C, and the volume of water in the pot will decrease, as it turns into steam and floats away from the pot.
4 0
3 years ago
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