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mestny [16]
2 years ago
13

Which interaction of nature depends on the distance through which it acts and is involved in beta decay? a. strong c. electromag

netic b. weak d. gravitational
Physics
1 answer:
USPshnik [31]2 years ago
5 0

The answer is weak.  The interaction of nature that will depend on the distance through the way it acts and involved in beta decay is the weak interaction or the weak force. This interaction is the responsible for radioactive decay which also plays a significant role in nuclear fission.

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An object is moving at 2.50 m/s [E]. At a time 3.00 seconds later the object is traveling at 1.50 m/s
babunello [35]

Given parameters:

First velocity  = 2.50m/s

Time of travel = 3s

Second velocity  = 1.50m/s

Unknown:

The displacement during the first interval = ?

Velocity is the displacement of a body with time. Displacement is a distance move in a specific direction by a body.

    Velocity  = \frac{Displacement}{Time taken}

So;

      Displacement  = Velocity x Time taken

Now input the parameter for the first velocity and time of travel;

      Displacement  = 2.5 x 3  = 7.5m

The displacement id 7.5m

7 0
3 years ago
What is the new volume of the gas if the pressure on 350 L of oxygen
Iteru [2.4K]

Answer:

420 L

Explanation:

Applying Boyle's Law,

PV = P'V'.................... Equation 1

Where P = Initial pressure, P' = Final pressure, V = Initial volume, V' = Final volume.

make V' the subject of the equation

V' = PV/P'.................... Equation 2

From the question,

Given: P = 720 mmHg, V = 350 L, P' = 600 mmHg

Substitute these values into equation 2

V' = (720×350)/600

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7 0
3 years ago
What is the speed of a cheetah if it takes 20 sesonds to run 300 m
natta225 [31]

the answer to your question is 15 :)

8 0
3 years ago
What quantity of heat must be removed from 20g<br>of water at 0°C to change it to ice at 0°C?​
seraphim [82]

The quantity of heat must be removed is 1600 cal or 1,6 kcal.

<h3>Explanation : </h3>

From the question we will know if the condition of ice is at the latent point. So, the heat level not affect the temperature, but it can change the object existence. So, for the formula we can use.

\boxed {\bold {Q = m \times L}}

If :

  • Q = heat of latent (cal or J )
  • m = mass of the thing (g or kg)
  • L = latent coefficient (cal/g or J/kg)
<h3>Steps : </h3>

If :

  • m = mass of water = 20 g => its easier if we use kal/g°C
  • L = latent coefficient = 80 cal/g

Q = ... ?

Answer :

Q = m \times L \\ Q = 20 \times 80 = 1600 \: cal

So, the quantity of heat must be removed is 1600 cal or 1,6 kcal.

<u>Subject : Physics </u>

<u>Subject : Physics Keyword : Heat of latent</u>

4 0
3 years ago
(r= -82) is a example of what correlation
coldgirl [10]

Answer:

the linear dependence between two variables

6 0
2 years ago
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