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3 years ago

5

Who was the first person to say that earth orbits the sun?

2 answers:

Whitepunk [10]3 years ago

7 0

The first person to say the Earth orbited the sun was Nicolaus Copernicus

defon3 years ago

3 0

Answer:

Nicolaus Copernicus (Mathematician)

Explanation:

Copernicus (1473-1543) was not the first person to claim that the Earth rotates around the Sun. In Western civilization, ancient Greek astronomer Aristarchus of Samos is generally credited with being the first person to propose a Sun-centred astronomical hypothesis of the universe (heliocentric).

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Maria is comparing data from an investigation about the melting point of ice. Based on her research, she knows ice

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Answer:

The answer Is set 4.

Explanation

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3 years ago

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hich muscle fibers are best suited for activities that involve lifting large, heavy objects for a short period of time? cardiac

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3 years ago

A ball is kicked at an angle of 35° with the ground.a) What should be the initial velocity of the ball so that it hits a target

stiks02 [169]

Answer:

a.18.5 m/s

b.1.98 s

Explanation:

We are given that

$\theta=35^{\circ}$

a.Let $v_0$ be the initial velocity of the ball.

Distance,x=30 m

Height,h=1.8 m

$v_x=v_0cos\theta=v_0cos35$

$v_y=v_0sin\theta=v_0sin35$

$x=v_0cos\theta\times t=v_0cos35\times t$

$t=\frac{30}{v_0cos35}$

$h=v_yt-\frac{1}{2}gt^2$

Substitute the values

$1.8=v_0sin35\frac{30}{v_0cos35}-\frac{1}{2}(9.8)(\frac{30}{v_0cso35})^2$

$1.8=30tan35-\frac{6574.6}{v^2_0}$

$\frac{6574.6}{v^2_0}=21-1.8=19.2$

$v^2_0=\frac{6574.6}{19.2}$

$v_0=\sqrt{\frac{6574.6}{19.2}}=18.5 m/s$

Initial velocity of the ball=18.5 m/s

b.Substitute the value then we get

$t=\frac{30}{18.5cos35}$

t=1.98 s

Hence, the time for the ball to reach the target=1.98 s

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3 years ago

Determine the angular velocity ω of the telescope as it orbits around the Sun.

lara31 [8.8K]

The JWST is postioned about 1.5 million kilometers from the earth on the side facing away from the sun

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2 years ago

With what force will a car hit a tree if the car has a mass of 3,415 kg and it is accelerating at

weeeeeb [17]

Answer:

$F= 17,075\ N$

Explanation:

When the car is under an accelerating force and hits a tree, the instant force received by the tree is the same force that is accelerating the car.

The accelerating force can be calculated using Newton's second law:

$F=m\cdot a$

Where m is the mass of the car and a is the acceleration.

$F=3,415\ kg\cdot 5\ m/s^2$

$\boxed{F= 17,075\ N}$

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3 years ago