Science is based on norms of scientific research, while pseudoscience does not.
8M.
Because it would acumúlate to it
Answer:
a) F = 1.26 10⁵ N, b) F = 2.44 10³ N, c) F_net = 1.82 10³ N directed vertically upwards
Explanation:
For this exercise we must use the relationship between momentum and momentum
I = Δp
F t = p_f -p₀
a) It asks to find the force
as the man stops the final velocity is zero
F = 0 - p₀ / t
the speed is directed downwards which is why it is negative, therefore the result is positive
F = m v₀ / t
F = 63.5 7.89 / 3.99 10⁻³
F = 1.26 10⁵ N
b) in this case flex the knees giving a time of t = 0.205 s
F = 63.5 7.89 / 0.205
F = 2.44 10³ N
c) The net force is
F_net = Sum F
F_net = F - W
F_net = F - mg
let's calculate
F_net = 2.44 10³ - 63.5 9.8
F_net = 1.82 10³ N
since it is positive it is directed vertically upwards
Answer:
The maximum force that can be applied without causing the two 43- kg crates to move is 2.7KN
Explanation:
Given data
μ coefficient of friction 0.31
mass of two crates =2*43kg
=86kg
Weight of the two crates =mg
Assuming g= 9.81m/s²
W =86*9.81= 843.66N
We know that force against friction is given by
W =μR
Where
μ is coefficient of static friction
R limiting force
To solve for let's make it the subject of the formula
R= W/μ
R=843.66/0.31
R= 2721.5N
R= 2.7KN