W = Fd
W = 1225 N x 10 m = 12250
So, C = kE°A/d
putting the values,
C
= 3.8 × 8.85×10^(-12) × 3.14×1.5×1.5 × 10^(-6)/0.43 × 10^(-3)
so, 1.02 × 10^(-13)
so the most appropriate answer is 2 ...that is
1.4 × 10^(-13) ....answer !!
<span>Using the formula (delta)U = Q - W, where delta U is the change in the internal energy, W is the work done by the system, and Q is the additional heat added to the system, we are able to determine that the internal change is a total of 2400j.</span>
Given data :
Work (W) = 1200 J ,
distance (S) = 20 m ,
Determine the Force applied to the box = ?
Work done = F. S
1200 = F . 20
F = 60 N
<em>Force applied to the box is 60 N</em>