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Amanda [17]
3 years ago
5

What current flows through a 2.54cm diameter rod of pure silicon that is 20cm long when 1000V is applied?

Physics
1 answer:
vfiekz [6]3 years ago
3 0

Answer: 0.0039\ A

Explanation:

Given

Diameter of the rod d=2.54\ cm

length of rod is l=20\ cm

Resistivity of silicon is \rho=6.4\times 10^2\ \Omega-m

cross-section of the rod A

\Rightarrow A=\dfrac{\pi d^2}{4}\\\\\Rightarrow A=\dfrac{3.142\times 2.54^2\times 10^{-4}}{4}\\\\\Rightarrow A=5.067\times 10^{-4}\ m^2

Resistance of rod is  R

\Rightarrow R=\dfrac{\rho l}{A}

\Rightarrow R=\dfrac{640\times 0.20}{5.067\times 10^{-4}}\\\\\Rightarrow R=25.26\times 10^4\ \Omega

Current is given by

\Rightarrow I=\dfrac{V}{R}\\\\\Rightarrow I=\dfrac{1000}{25.26\times 10^4}\\\\\Rightarrow I=0.0039\ A

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20. Using the picture, how many neutrons does lithium have?
Igoryamba

Answer:

No. of Neutrons = 3

Explanation:

The atomic number of Lithium is given as 3 in the symbol while the mass number is given as 5.941 which is approximately equal to 6.

Mass Number = No. of Protons + No. of Neutrons = 6

Atomic Number = Number of Electrons = No. of Protons = 3

Therefore,

Mass Number - Atomic Number = (No. of Protons + No. of Neutrons) - No. of Protons

Mass Number - Atomic Number = No. of Neutrons

No. of Neutrons = 6 - 3

<u>No. of Neutrons = 3 </u>

8 0
3 years ago
A spacecraft and a staellite are at diametrically opposite position in the same circular orbit of altitude 500 km above the eart
Tanya [424]

Answer:

Hello the diagram related to your question is attached below

answer: a) 851 m/s

             b)  8506.1 secs

Explanation:

calculate the periodic time of the satellite using the equation below

t = \frac{2\pi }{R} \sqrt{\frac{(R+h)^{3} }{g} }  --  ( 1 )

where ; R = 6370 km

h = 500 km

g = 9.81 m/s^2

input given values into equation 1

t = 5670.75 secs

next calculate the periodic time taken by the space craft  

<u>a) determine the increase in speed </u>

V = v - \sqrt{\frac{gR^2}{R + h} }  

where ; v = 8463 m/s , R = 6370 km, h = 500 km

V = 851 m/s

b) Determine the periodic time for the elliptic orbit

τ = \frac{3t}{2}

 = \frac{3*5670.76}{2}  =  8506.1 secs

attached below is the remaining part of the detailed solution

5 0
3 years ago
A car accelerates uniformly from +10.0 m/s to +40.0 m/s over a distance of 125 m. How long did it take to go that distance? Show
Marizza181 [45]

Answer:

Explanation:

v^2-u^2=2as\\40^2-10^2=2a*125\\1600-100=250a\\a=\frac{1500}{250}=6~m/s^2\\v=u+at\\40=10+6t\\6t=30\\ t=\frac{30}{6}=5 ~s

7 0
3 years ago
Each of 134 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first bl
poizon [28]

Answer:

A. T=126N

B. T=63N

Explanation:

To determine the tension in each given blocks, we first determine the acceleration of each block. It obvious that each mass will move with the same acceleration since the string connecting them is massless.

Hence using the equation of force we have

F=ma

Where m=total mass of blocks,

a=acceleration

F= force applied in this case the tension in the string.

For a 134 identical masses with an applied force of 134N, the acceleration of each mass can be computed as

134=134m*a

a=134/134m

a=(1/m )m/s²

a. To calculate the tension in the string between the 126 and 127 block, we use the equation below

T=ma

Since the number of blocks before the string is 126, we multiply the mass of each block by 126.

Hence the tension can be computed as

T=126m*a

Since a=1/m then

T=126m*1/m

T=126N

B.To calculate the tension in the string between the 63 and 64 block, we use the equation below

T=ma

Since the number of blocks before the string is 63, we multiply the mass of each block by 63.

Hence the tension can be computed as

T=63m*a

Since a=1/m then

T=63m*1/m

T=63N

8 0
4 years ago
A camcorder has a power rating of 16 watts. If the output voltage from its battery is 9 volts, what current does it use?
Sphinxa [80]
Because of the parameters that we are given in the question, the right current formula that should be used for this physics problem is:
I = P/V
Where:
I = Current
P = Power  and 
V = Voltage
From the question, we are told that:
P = 16 W
V = 9 V
Thus, current = P/V = 16/9 = 1.78
Therefore, The current used by the camcorder is 1.8 Amphere. 
8 0
3 years ago
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