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Umnica [9.8K]
3 years ago
14

G.o has 3 orange picks for every 2 green. if there are 25 picks in all how many picks are orange

Mathematics
1 answer:
V125BC [204]3 years ago
6 0

Answer:

15 orange picks.

Step-by-step explanation:

We need to split 25 according to the ratio 3:2.

So the number of orange picks = 25 * (3 / (3+2)

= 25 * 3/5

= 15.

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The drummer drove 18 miles to pick up the singer and then another 28 miles to the job. The rest of the band drove 52 miles to th
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The rest of the band drove more and by 6 miles.

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Use long division to find the quotient below.
Svetradugi [14.3K]
X^3+3x^2-18x-3x^2-9x+54
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X^3-27x+54


I hope you understand my explanation and best of wishes!!
5 0
3 years ago
The amount of soda dispensing machine pours into a can of soda is normally distributedwith a mean of 12 ounces and a standard de
kaheart [24]

Answer:

0.1056

Step-by-step explanation:

Mean(μ) = 12 ounce

Standard deviation (σ) = 0.2 ounce

P(x<11.75) = ???

Let x be the random variable for the amount of soda a machine will dispense.

Using normal distribution

Z = (x - μ) / σ

Z = (11.75 - 12) / 0.2

Z = (-0.25)/0.2

Z = -1.25

From the normal distribution table

1.28 is 0.3944

Φ(z) is the tabular value of z

Φ(z) = 0.3944

Recall that when Z is negative

P(x<a) = 0.5 - Φ(z)

P(x < 11.75) = 0.5 - 0.3944

= 0.1056

7 0
3 years ago
A study was conducted to determine whether magnets were effective in treating pain. The values represent measurements of pain us
Zanzabum

Answer:

Step-by-step explanation:

Hello!

The objective of the study is to determine whether the magnets are effective in treating pain. For these two independent groups of individuals with equal affections were randomly sampled, one was treated with magnets and the other group of individuals, call it control group, was treated with a placebo treatment.

The information for both samples is:

X₁: pain measurement using a visual analog scale after the individual received magnet treatments.

X₁~N(μ₁;σ₁²)

n₁= 20

X[bar]₁= 0.46

S₁= 0.93

X₂: pain measurement using a visual analog scale of an individual of the control groups.

X₂~N(μ₂;σ₂²)

n₂= 20

X[bar]₂= 0.41

S₂= 1.26

The claim is that the pain reductions of the control group have more variation than the pain reductions of the target group. If it's so then we could suspect that the population variance of the control group, σ₂², will be greater than the population variance of the magnet group, σ₁².

To test the relationship between these two population variances you have to conduct a variance ratio test using the Snedecors F statistic.

The hypotheses are:

H₀: σ₂² ≤ σ₁²

H₁: σ₂² > σ₁²

α: 0.05

F= (\frac{S_2^2}{S_1^2}) * (\frac{Sigma_2^2}{Sigma_1^2} )~~ F_{(n_2-1);(n_1-1)}

This hypothesis test is one-tailed to the right, there is only one critical value:

F_{(n_2-1);(n_1-1); 1 - \alpha } = F_{19;19; 0.95}= 2.17

The decision rule for the test is:

If F_{H_0} ≥ 2.17, then the decision is to reject the null hypothesis.

If F_{H_0} < 2.17, then the decision is to not reject the null hypothesis.

F_{H_0}= \frac{S_2^2}{S_1^2}*\frac{Sigma_2^2}{Sigma_1^2}  = \frac{(1.26)^2}{(0.93)^2} * 1

F_{H_0} = 1.835 = 1.84

Since the calculated value of F is less than the critical value, the decision is to reject the null hypothesis. So using a 5% significance level the decision is to not reject the null hypothesis, you can conclude that the population variance of the pain reduction of the control group is less or equal than the population variance of the pain reduction on individuals treated with magnets.

I hope it helps!

3 0
3 years ago
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