Does aluminum conduct electricity?
1 answer:
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Answer:
A. 10.0 grams of ethyl butyrate would be synthesized.
B. 57.5% was the percent yield.
C. 7.80 grams of ethyl butyrate would be produced from 7.60 g of butanoic acid.
Explanation:
A
Moles of butanoic acid =
According to reaction ,1 mole of butanoic acid gives 1 mol of ethyl butyrate,then 0.08636 mol of butanoic acid will give :
of ethyl butyrate
Mass of 0.08636 moles of ethyl butyrate =
0.08636 mol × 116 g/mol = 10.0 g
Theoretical yield = 10.0 g
Experimental yield = ?
Percentage yield of the reaction = 100%
Experimental yield = 10.0 g
10.0 grams of ethyl butyrate would be synthesized.
B
Theoretical yield of ethyl butyrate = 10.0 g
Experimental yield ethyl butyrate = 5.75 g
Percentage yield of the reaction = ?
57.5% was the percent yield.
C
Moles of butanoic acid =
According to reaction ,1 mole of butanoic acid gives 1 mol of ethyl butyrate,then 0.08636 mol of butanoic acid will give :
of ethyl butyrate
Mass of 0.08636 moles of ethyl butyrate =
0.08636 mol × 116 g/mol = 10.0 g
Theoretical yield = 10.0 g
Experimental yield = ?
Percentage yield of the reaction = 78.0%
Experimental yield = 7.80 g
7.80 grams of ethyl butyrate would be produced from 7.60 g of butanoic acid.
Answer:
B
Explanation:
This question is about stoichiometry. From the balanced equation ⇒
, we see that 3 moles of water is needed to react with 1 mole of
.
This means that, to fully react 3.62 moles of , we would need 3*3.62 or 10.86 moles of water. However, we only have 6.31 moles, so water is the limiting reactant.
Since 3 moles of water react with 1 mole of , 6.31 moles of water can fully react with 6.31÷3 or 2.1033 moles of
.
From the balanced equation, we see that every mole of reacted gets you 2 moles of
. Therefore, 2.1033 moles of
would give you approximately 4.21 moles of
.