Answer:
The amount of heat released when 50 g of water cooled from 20°C to 10°C will be equal to - 2093 J.
Explanation:
Given data:
Mass of water = 50 g
Initial temperature= T1 = 20°C
Final temperature= T2 = 10°C
Specific heat of water= c = 4.186 J/g. °C
Amount of heat released = Q= ?
Solution:
Formula:
Q = m. C. ΔT
ΔT = T2 - T1
ΔT = 10°C - 20°C
ΔT = -10°C
Now we will put the values in formula.
Q = m. C. ΔT
Q = 50 g . 4.186 J/g. °C . -10°C
Q = - 2093 J
The amount of heat released when 50 g of water cooled from 20°C to 10°C will be equal to - 2093 J.
The energy generated by the movement of electrons is used to pump electrons across the inner mitochondrial membrane to an area of higher concentration. 17. Where do these protons (H+) come from? The originally came from a glucose molecule and were carried to the electron transport chain by NADH and FADH2.
The answer would be glucose molecule.
X= (3*2)(31.75)/(2*17)3*31.75/17
=5.603g H2
Answer: 5.603g H2
It’s all quite simple actually considering the fact the M(NH3) = 14 + 1*3 = 17g/mol
And M(H2) = 2*1 2g/mol
So 3H2 + N2 >> 2NH3
Givin that Xg is 31.75g
-HOPE THAT HELPED IN A WAY!!☺️
Answer:
C. product costs and expensed when the goods are sold
Explanation:
No I can’t
EXAMPLE took the test k12
