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JulsSmile [24]
3 years ago
5

What is true about valence electrons?

Physics
2 answers:
luda_lava [24]3 years ago
8 0
The valence electrons are the one furthest from the nucleus
Fiesta28 [93]3 years ago
5 0

Answer:

furthest from the nukelest

Explanation:

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Cloud [144]

Answer:

broom

Explanation:

8 0
3 years ago
Marco is conducting an experiment. He knows the wave that he is working with has a wavelength of 32. 4 cm. If he measures the fr
sineoko [7]

The true statement about the wave is that, the wave has traveled 97. 2 cm in 1 second.

In Physics, we define a wave as a disturbance along a medium that transfers energy. The wavelength of a wave is the distance covered by the wave while the frequency of the wave is the number of cycles of the wave completed per second.

The period of the wave is the inverse of the frequency of the wave. It is defined as the time taken for the wave to complete a cycle and it is measured in seconds.

The wave formula is given as;

v = λf

v = velocity of the wave (distance traveled by the wave in one second)

λ = wavelength of the wave

f = frequency of the wave

So;

λ = 32.4 cm

f =  3 hertz

v = 32.4 cm × 3 hertz

v = 97. 2 cms-1

Hence, the true statement about the wave is that, the wave has traveled 97. 2 cm in 1 second.

Learn more: brainly.com/question/14588679

7 0
2 years ago
a person is sitting on the last bench can see clearly see things written on book but cannot see them distinctly on board. what t
marysya [2.9K]

Answer:

I think concave

Explanation:

7 0
3 years ago
If the horizontal component of a vector is 6 m/s and the vertical component is also 6 m/s, what is the resultant value of the ve
BlackZzzverrR [31]
Resultant force= (2*6^2)^(1/2)
=8.5m/s
answer is B.
6 0
3 years ago
Ask Your Teacher Cam Newton of the Carolina Panthers throws a perfect football spiral at 6.9 rev/s. The radius of a pro football
faltersainse [42]

Answer:

a=159.32\ m/s^2

Explanation:

It is given that,

Angular speed of the football spiral, \omega=6.9\ rev/s=43.35\ rad/s

Radius of a pro football, r = 8.5 cm = 0.085 m

The velocity is given by :

v=r\omega

v=0.085\times 43.35

v = 3.68 m/s

The centripetal acceleration is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(3.68)^2}{0.085}

a=159.32\ m/s^2

So, the centripetal acceleration of the laces on the football is 159.32\ m/s^2. Hence, this is the required solution.

6 0
3 years ago
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