Using the Equation:
v² = vi² + 2 · a · s → Eq.1
where,
v = final velocity
vi = initial velocity
a = acceleration
s = distance
<span><span>We know that vi = 0 because the ball was at rest initially.
</span><span>
Therefore,
Solving Eq.1 for acceleration,
</span></span> v² = vi² + 2 · a · s
v² = 0 + 2 · a · s
v² = 2 · a · s
Rearranging for a,
a = v ²/2·<span>s
Substituting the values,
a = 46</span>²/2×1<span>
a = 1058 m/s</span>²
<span>Now applying Newton's 2nd law of motion,
</span>
<span>F = ma
= 0.145</span>×<span>1058
F = 153.4 N</span>
Answer:
2 charges of electron (2C)
Explanation:
I = Q/t
2 = Q/1
Q = 2×1= 2C
Q = 2 charge of electron
Answer:
292.31 m/s
Explanation:
If Distance (d) = 190m
Time (t) = 1.3s
Speed of sound in air (v) =?
then
2d=vt
v=2d/t
v= 2×190/1.3
v=292.31 m/s
When a sound source is moving toward you, you hear a higher frequency than the source is putting out, and when the source is moving away from you, you hear a lower frequency than the real one. The whole process is called the Doppler effect. It works with light too.
